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首页> 外文期刊>Journal of Mathematical Biology >Finding a most parsimonious or likely tree in a network with respect to an alignment
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Finding a most parsimonious or likely tree in a network with respect to an alignment

机译:在网络中寻找一个最常见的或可能的树,相对于对齐方式

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Phylogenetic networks are often constructed by merging multiple conflicting phylogenetic signals into a directed acyclic graph. It is interesting to explore whether a network constructed in this way induces biologically-relevant phylogenetic signals that were not present in the input. Here we show that, given a multiple alignment A for a set of taxa X and a rooted phylogenetic network N whose leaves are labelled by X, it is NP-hard to locate a most parsimonious phylogenetic tree displayed by N (with respect to A) even when the level of N-the maximum number of reticulation nodes within a biconnected component-is 1 and A contains only 2 distinct states. (If, additionally, gaps are allowed the problem becomes APX-hard.) We also show that under the same conditions, and assuming a simple binary symmetric model of character evolution, finding a most likely tree displayed by the network is NP-hard. These negative results contrast with earlier work on parsimony in which it is shown that if A consists of a single column the problem is fixed parameter tractable in the level. We conclude with a discussion of why, despite the NP-hardness, both the parsimony and likelihood problem can likely be well-solved in practice.
机译:通过将多个冲突的系统发育信号与定向的非循环图合并来构建系统发育网络。探索以这种方式构建的网络是否诱导了在输入中不存在的生物学上相关的系统发育信号是有趣的。在这里,我们认为,给定一组分类×x和叶片被X标记的生根发育网络n的多个对准A,它是np-难以定位由n(相对于a)显示的最令人杀灭的系统发育树即使当BIConnated组件中的N-最大的网状速度节点的水平也是1和A仅包含2个不同状态。 (如果另外,允许空白允许问题变为APX-Hard。)我们还显示在相同的条件下,并假设字符演变的简单二进制对称模型,找到由网络显示的最可能的树是NP-HARD。这些负面结果与早期的关于关于的概要对比,其中显示,如果A由单列组成,则问题是固定的参数在级别中的Tractable。我们在讨论为什么,尽管存在NP的硬度,但各种各样的概念和可能性问题都可能在实践中得到很好解决。

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