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Total relative displacement of vertex permutations of K-n1, (n2),...,(nt)

机译:K-N1,(N2),...,(NT)的顶点哺乳的总相对位移

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Let c, denote a permutation of the n vertices of a connected graph G. Define delta(alpha)(G) to be the number Sigmad(x,y)-d(alpha(x),alpha(y)), where the sum is over all the ((n)(2)) unordered pairs of distinct vertices of G. The number delta(alpha)(G) is called the total relative displacement of alpha (in G). So, permutation alpha is an automorphism of G if and only if delta(alpha)(G)=0. Let pi(G) denote the smallest positive value of delta(alpha)(G) among the nl permutations alpha of the vertices of G. A permutation alpha for which pi(G)=delta(alpha)(G) has been called a near-automorphism of G [2] We determine pi(k(n 1,n 2,...n t)) and describe permutations alpha K-n 1,K-n2,K-...n t for which pi(K-n 1,K-n 2,K-...n t) = deltaalpha(K-n 1,K-n 2,K-...n t). This is done by transforming the problem into the combinatorial optimization problem of maximizing the sums of the squares of the entries in certain tby tmatrices with non-negative integer entries in which the sum of the entries in the ith row and the sum of the entries in the ith column each equal to n(jt) 1 less than or equal to i less than or equal to t. We prove that for positive integers, n(1) less than or equal to n(2) < &BULL;&BULL;&BULL; &LE; n(t), where t &GE; 2 and n(t) &GE; 2, [GRAPHICS] where k(0) is the smallest index for which n(k 0)+1 = n(k 0)+1. As a special case, we correct the value of π(K-m,K-n), for all m and n at least 2, given by Chartrand, Gavlas, and VanderJagt [2]. (C) 2002 Wiley Periodicals, Inc. [References: 2]
机译:让C,表示连接图G的n顶点的置换。将增量(alpha)(g)定义为数字sigma d(x,y)-d(a​​lpha(x),alpha(y)) ,其中总和超过所有((2))的G. Number Delta(α)(g)的不同顶点的无序顶点被称为α的总相对位移(在g)中。因此,置换alpha是g如果Δ(alpha)(g)= 0的自动形态。让pi(g)表示G的NL释放α之间的Δ(α)(g)的最小正值。Pi(g)= delta(alpha)(g)被称为a的折射α G [2]近的自同一族,我们确定PI(k(n 1,n 2,... nt))和描述αkn 1,k-n2,k-.. nt(kn 1, kn 2,k -... nt)= deltaalpha(kn 1,kn 2,k -... nt)。这是通过将问题转换为组合优化问题来完成的,其中包含具有非负整数条目的某些TY TMatrices中条目的正方形的总和,其中第i行中的条目和条目之和中的条目之和第i个列等于n(jt)1小于或等于i小于或等于t。我们证明对于正整数,n(1)小于或等于n(2)<&bull;&bull; &le; n(t),其中t e; 2和n(t)&ge; 2,[图形]其中k(0)是n(k 0)+1 = n(k 0)+1的最小索引。作为一个特殊情况,我们校正了由Chartrand,Gavlas和Vanderjagt给出的所有m和n至少2的所有m和n的值的值和pi; (c)2002 Wiley期刊,Inc。[参考文献:2]

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