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On stars and Steiner stars

机译:在星星和施泰纳星

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摘要

A Steiner star for a set P of n points in R-d connects an arbitrary point in R-d to all points of P, while a star connects one of the points in P to the remaining n - 1 points of P. All connections are realized by straight line segments. Let the length of a graph be the total Euclidean length of its edges. Fekete and Meijer showed that the minimum star is at most root 2 times longer than the minimum Steiner star for any finite point configuration in R-d. The supremum of the ratio between the two lengths, over all finite point configurations in R-d, is called the star Steiner ratio in R-d. It is conjectured that this ratio is 4/pi = 1.2732... in the plane and 4/3 = 1.3333... in three dimensions. Here we give upper bounds of 1.3631 in the plane, and 1.3833 in 3-space. These estimates yield improved upper bounds on the maximum ratios between the minimum star and the maximum matching in two and three dimensions. We also verify that the conjectured bound 4/pi in the plane holds in two special cases. Our method exploits the connection with the classical problem of estimating the maximum sum of pairwise distances among n points on the unit sphere, first studied by Laszlo Fejes Toth. It is quite general and yields the first nontrivial estimates below root 2 on the star Steiner ratios in arbitrary dimensions. We show, however, that the star Steiner ratio in R-d tends to root 2 as d goes to infinity. As it turns out, our estimates are related to the classical infinite Wallis product: pi/2 = Pi(infinity)(n=1) (4n(2)/4n(2)-1) = 2/1 . 2/3 . 4/3 . 4/5 . 6/5 . 6/7. 8/7 . 8/9 ....
机译:RD中N点的SET ST的施蒂纳星将RD的任意点连接到P的所有点,而星星将P中的一个点连接到剩余的N - 1点。所有连接都是直线实现的线段。让图表的长度是其边缘的总欧几里德长度。 Fekete和Meijer表明,最小明星最多的根部比R-D中的任何有限点配置的最小静脉恒星长2倍。在R-D中的所有有限点配置中,两个长度之间的比率的高度称为R-D中的星形静脉比。猜测该比率在飞机中为4 / pi = 1.2732 ......在三维中4/3 = 1.3333 ......在这里,我们在飞机上提供1.3631的上限,3个空间中的1.3833。这些估计产生了最大明星和两个和三维最大匹配之间的最大比率的改善的上限。我们还验证了飞机中的猜测绑定4 / PI在两个特殊情况下持有。我们的方法利用了与估计单位球体上的N点之间的最大成对距离的最大问题的经典问题的连接,首先由Laszlo Fejes Toth研究。它是一般的,并在任意尺寸下,在星形施坦醚比例下,在根2下方的第一个非估计。然而,我们展示了R-D中的明星施蒂纳比倾向于根2,因为d进入无穷大。事实证明,我们的估计与经典无限壁产品有关:PI / 2 = PI(无穷大)(n = 1)(4N(2)/ 4N(2)-1)= 2/1。 2/3。 4/3。 4/5。 6/5。 6/7。 8/7。 8/9 ....

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