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On the comparability of cardinals in the absence of the axiom of choice

机译:基于首选缺失的红衣主教的可比性

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摘要

It is a well-known result of Hartogs' that the statement "for all sets x and y, x = y or y = x (where 'x = y' means that there is a one-to-one map f : x - y)" is equivalent to the Axiom of Choice (AC) (the latter in the disguise of the well-ordering theorem, i.e., "every set can be well-ordered"). A considerably stronger result by Tarski states that for any natural number n = 2, the statement "if x is a set consisting of n sets, then there exist distinct elements y, z is an element of x such that y = z or z = y" is equivalent to AC.
机译:它是Hartogs的众所周知的结果,即所有集合x和y,x& = y或y& = x(其中'x = y'意味着有一对一的 一个地图f:x - & y)“相当于首选的公理(AC)(后者在伪装定理的伪装中,即”每组都可以是众所序的套件“)。 tarski指出的结果具有相当强烈的结果,即对于任何自然数n& = 2,声明“如果x是由n lea组成的集合,则存在不同的元素y,z是x的元素,使得y <= z或z& = y“相当于AC。

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