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Sufficient condition for nonexistence of symmetric extension of qudits using Bell inequalities

机译:使用Bell Inequality的Quditric扩展不存在的足够条件

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We analyze the connection between Bell inequality violations and symmetric extendibility of quantum states. We prove that 2-qubit reduced states of multiqubit symmetric pure states do not violate the Bell Clauser- Horne-Shimony-Holt (CHSH) inequality. We then prove the more general converse that any 2-qubit state that violates the CHSH inequality cannot have a symmetric extension. We extend our analysis to qudits and provide a test for symmetric extendibility of 2-qudit states. We show that if a 2-qudit Bell inequality is monogamous, then any 2-qudit state that violates this inequality does not have a symmetric extension. For the specific case of 2-qutrit states, we use numerical evidence to conjecture that the Collins-Gisin-Linden-Massar-Popescu (CGLMP) inequality is monogamous. Hence, the violation of theCGLMPinequality by any 2-qutrit state could be a sufficient condition for the nonexistence of its symmetric extension.
机译:我们分析了贝尔不等式违规与量子态对称可扩展的连接。 我们证明了2-QUB减少的多谜语对称纯粹状态的态度不会违反钟声 - Horne-Shimony-Holt(CHSH)不等式。 然后,我们证明了违反CHSH不等式的任何2个Qubit状态的一般性关系越一般而言,不能具有对称的扩展。 我们将分析扩展到QUDITS和提供2 QUDIT状态的对称可扩展性测试。 我们表明,如果2 Qudit Bell Inequality是一条单一的,那么违反此不等式的任何2 Qudit状态都没有对称扩展。 对于2-Qutrit州的具体情况,我们使用数值证据来召集Collins-Gisin-Linden-Massar-Popescu(CGLMP)不等式是一般性的。 因此,任何2-Qutrit状态违反了该模糊状态可能是其对称延伸不存在的足够条件。

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