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首页> 外文期刊>Physical chemistry chemical physics: PCCP >Where does methanol lose hydrogen to trigger steam reforming? A revisit of methanol dehydrogenation on the PdZn alloy model obtained from kinetic Monte Carlo simulations
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Where does methanol lose hydrogen to trigger steam reforming? A revisit of methanol dehydrogenation on the PdZn alloy model obtained from kinetic Monte Carlo simulations

机译:甲醇在哪里损失氢气以触发蒸汽重整?从动力学蒙特卡洛模拟获得的PdZn合金模型上对甲醇脱氢的再探讨

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摘要

Pd/ZnO is a promising catalyst studied for methanol steam reforming (MSR) and the 1 : 1 PdZn alloy is demonstrated to be the active component. It is believed that MSR starts from methanol dehydrogenation to methoxy. Previous studies of methanol dehydrogenation on the ideal PdZn(111) surface show that methanol adsorbs weakly on the PdZn(111) surface and it is hard for methanol to transform into methoxy because of the high dehydrogenation barrier, indicating that the catalyst model is not appropriate for investigating the first step of MSR. Using the model derived from our recent kinetic Monte Carlo simulations, we examined the process CH3OH -> CH3O -> CH2O -> CHO -> CO. Compared with the ideal model, methanol adsorbs much more strongly and the barrier from CH3OH -> CH3O is much lower on the kMC model. On the other hand, the C-H bond breaking of CH3O, CH2O and CHO becomes harder. We show that co-adsorbed water is important for refreshing the active sites. The present study shows that the first MSR step most likely takes place on three-fold hollow sites formed by Zn atoms, and the inhomogeneity of the PdZn alloy may exert significant influences on reactions.
机译:Pd / ZnO是研究甲醇蒸汽重整(MSR)的有前途的催化剂,已证明1:1的PdZn合金是活性成分。据信MSR是从甲醇脱氢到甲氧基开始的。以前在理想的PdZn(111)表面进行甲醇脱氢的研究表明,甲醇在PdZn(111)表面上的吸附较弱,并且由于高的脱氢势垒,甲醇很难转化为甲氧基,这表明催化剂模型不合适用于调查MSR的第一步。使用我们最近的动力学蒙特卡洛模拟得出的模型,我们检查了CH3OH-> CH3O-> CH2O-> CHO-> CO过程。与理想模型相比,甲醇吸附更强,而CH3OH-> CH3O的阻挡层为在kMC模型上要低得多。另一方面,CH 3 O,CH 2 O和CHO的C-H键断裂变得更难。我们表明,共吸附水对于刷新活性部位很重要。本研究表明,MSR的第一步很可能发生在锌原子形成的三重空心位点上,PdZn合金的不均匀性可能会对反应产生重大影响。

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