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Evaluation of bioenergy recovery processes treating organic residues from ethanol fermentation process

机译:评价乙醇发酵过程中有机残留物的生物能回收过程

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This study evaluates a two-stage bioprocess for recovering bioenergy in the forms of hydrogen and methane while treating organic residues of ethanol fermentation from tapioca starch. A maximum hydrogen production rate of 0.77mmolH_2/gVSS/h can be achieved at volumetric loading rate (VLR) of 56kgCOD/m~3/day. Batch results indicate that controlling conditions at S_0/X_0=12 with X_0=4000mgVSS/L and pH 5.5-6 are important for efficient hydrogen production from fermentation residues. Hydrogen-producing bacteria enriched in the hydrogen bioreactor are likely utilizing lactate and acetate for biohydrogen production from ethanol-fermentation residues. Organic residues remained in the effluent of hydrogen bioreactor can be effectively converted to methane with a rate of 0.37mmol CH_4/gVSS/h at VLR of 8kg COD/m~3/day. Approximately 90% of COD in ethanol-fermentation residues can be removed and among that 2% and 85.1% of COD can be recovered in the forms of hydrogen and methane, respectively.
机译:这项研究评估了一个两阶段的生物过程,用于回收氢和甲烷形式的生物能,同时处理木薯淀粉中乙醇发酵的有机残留物。在56kgCOD / m〜3 / day的体积负荷率(VLR)下,最大制氢速率为0.77mmolH_2 / gVSS / h。分批结果表明,将X_0 = 4000mgVSS / L和pH 5.5-6控制在S_0 / X_0 = 12的条件对于从发酵残留物中高效产氢很重要。富含氢生物反应器的产氢细菌很可能利用乳酸和乙酸盐从乙醇发酵残留物中生产生物氢。在8kg COD / m〜3 / day的VLR下,残留在氢气生物反应器流出物中的有机残留物可以0.37mmol CH_4 / gVSS / h的速率有效地转化为甲烷。可以去除乙醇发酵残渣中大约90%的COD,其中2%和85.1%的COD可以分别以氢气和甲烷的形式回收。

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