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首页> 外文期刊>Journal of the Chemical Society, Dalton Transactions. Inorganic Chemistry >Five-coordinate complexes of palladium(II) and platinum(II) with alpha-diimine and 1,5-cyclooctadiene ligands
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Five-coordinate complexes of palladium(II) and platinum(II) with alpha-diimine and 1,5-cyclooctadiene ligands

机译:钯(II)和铂(II)与α-二亚胺和1,5-环辛二烯配体的五配位络合物

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摘要

The five-coordinate complexes [PtMe(cod)(N-N')]BF4 [cod = eta(2), eta(2)-cyclooctadiene, N-N' = (6-R-2)C5H3N-2-CH=NR1 (R-1 = C6H4OMe-4, R-2 = H (1), Me (2); R-1 = CMe3, R-2 = H (3), Me (4); R-1 = (R)-bornyl, R-2 = Me (5))] are readily obtained from the reaction of [PtClMe(cod)] with N-N' in the presence of NaBF4. The preparation of [PtMe(cod)(6)]BF4 (6 = 4-MeOC6H4N=CHCHN=C6H4OMe-4), [PdMe(cod)(N-N')] BF4 and [PtCl(cod)(N-N')]BF4 (N-N' = 2, 4) requires chloride abstraction by AgBF4 from [PtClMe(cod)], [PdClMe(cod)] and [PtCl2(cod)], respectively, followed by coordination of N-N'. The NMR spectral data suggest a trigonal-bipyramidal structure with chelating cod and N-N' ligands, where the alpha-diimine and one C=C bond are on the equatorial plane and the second C=C bond in an axial position. The complexes [PtMe(cod)(1)]BF4 and [PtCl(cod)(2)]BF4 undergo dynamic processes in solution which bring about N-N' ligand site exchange for the former, and exchange of all the olefinic protons for the latter. The X-ray diffraction analysis of [PtMe(cod)(2)]BF4 indicates that in the solid state, the complex assumes a distorted trigonal-bipyramidal geometry, similar to that proposed to exist in solution. For the two independent molecules in the asymmetric unit cell, the differences in the structural parameters between the equatorial Pt-(CH=CH) bond [Pt-C2.08(1), 2.09(2) Angstrom, C=C 1.43(2) Angstrom (molecule I); Pt-C 2.13( 2), 2.10(2) Angstrom, C=C 1.42(2) Angstrom (molecule II)] and the axial Pt-(CH=CH) bond [Pt-C 2.35(1), 2.34(1) Angstrom, C=C 1.39(2) Angstrom (molecule I); Pt-C 2.37(2), 2.34(1) Angstrom, C=C 1.38(2) Angstrom (molecule II)] are related to the high trans influence of the methyl ligand and to greater d-pi back-donation in the equatorial bond. [References: 35]
机译:五坐标配合物[PtMe(cod)(N-N')] BF4 [cod = eta(2),eta(2)-环辛二烯,NN'=(6-R-2)C5H3N-2-CH = NR1 (R-1 = C6H4OMe-4,R-2 = H(1),Me(2); R-1 = CMe3,R-2 = H(3),Me(4); R-1 =(R) β-冰片基,R-2 = Me(5))]容易从[PtClMe(cod)]与NN'在NaBF4存在下的反应中获得。 [PtMe(cod)(6)] BF4(6 = 4-MeOC6H4N = CHCHN = C6H4OMe-4),[PdMe(cod)(N-N')] BF4和[PtCl(cod)(N-N)的制备')] BF4(NN'= 2,4)需要通过AgBF4从[PtClMe(cod)],[PdClMe(cod)]和[PtCl2(cod)]分别提取氯化物,然后配位N-N'。 NMR光谱数据表明具有螯合的鳕鱼和N-N'配体的三角-双锥体结构,其中α-二亚胺和一个C = C键位于赤道面上,第二个C = C键位于轴向位置。配合物[PtMe(cod)(1)] BF4和[PtCl(cod)(2)] BF4在溶液中经历动态过程,从而导致前者的NN'配体位点交换,以及所有烯烃质子的交换。 。 [PtMe(cod)(2)] BF4的X射线衍射分析表明,在固体状态下,该络合物呈扭曲的三角双锥面几何形状,类似于拟在溶液中存在的几何形状。对于不对称晶胞中的两个独立分子,赤道Pt-(CH = CH)键之间的结构参数差异[Pt-C2.08(1),2.09(2)埃,C = C 1.43(2 )埃(分子I); Pt-C 2.13(2),2.10(2)埃,C = C 1.42(2)埃(分子II)]和轴向Pt-(CH = CH)键[Pt-C 2.35(1),2.34(1) )埃,C = C 1.39(2)埃(分子I); Pt-C 2.37(2),2.34(1)埃,C = C 1.38(2)埃(分子II)]与甲基配体的高反式影响和赤道仪中更大的d-pi回赠有关键。 [参考:35]

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