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首页> 外文期刊>Journal of biological inorganic chemistry: JBIC: a publication of the Society of Biological Inorganic Chemistry >Disproportionation of pentaammineruthenium(III)–nucleoside complexes leads to two-electron oxidation of nucleosides without involving oxygen molecules
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Disproportionation of pentaammineruthenium(III)–nucleoside complexes leads to two-electron oxidation of nucleosides without involving oxygen molecules

机译:五氨合钌(III)-核苷络合物的歧化导致核苷的两电子氧化而不涉及氧分子

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Pentaammineruthenium(III) complexes of deoxyinosine (dIno) and xanthosine (Xao) ([Ru~(III)(NH_3)_5 (L)], L is dIno, Xao) in basic solution were studied by UV– vis spectroscopy, liquid chromatography/electrospray ionization mass spectrometry, and high-performance liquid chromatography. Both Ru~(III) complexes disproportionate to Ru~(II) and RuIV. Disproportionation followed the rate law d[Ru~(II)]/dt = (k_o + k_1[OH~-])[Ru~(III)]. k_o and k_1 of disproportionation at 25 °C were 2.1 (±0.1) 9 10~(-3) s~(-1) and 21.4 ± 3.2 M~(-1) s~(-1), respectively, for [Ru~(III)(NH_3)_5(dIno)], and 3.5 (±0.7) 9 10~(-4) s~(-1) and 59.7 ± 3.6 M~(-1) s~(-1), respectively, for [Ru~(III)(NH_3)_5(Xao)]. The [Ru~(III)(NH_3)_5 (Xao)] complex disproportionates at a faster rate than [Ru~(III)(NH_3)_5(dIno)] owing to the stronger electron-withdrawing effect of exocyclic oxygen in Xao. The activation parameters ΔH~? and ΔS~? for k_1 of [Ru~(III)(NH_3)_5(dIno)] were 80.2 ± 15.2 kJ mol~(-1) and 47.6 ± 9.8 J K~(-1) mol~(-1), respectively, indicating that the disproportionation of Ru~(III) to Ru~(II) and RuIV is favored owing to the positive entropy of activation. The final products of both complexes in basic solution under Ar were compared with those under O_2. Under both conditions [Ru(NH_3)_5(8-oxo-L)] was produced, but via different mechanisms. In both aerobic and anaerobic conditions, the deprotonation of highly positively polarized C8-H of Ru-L by OH~- initiates a two-electron redox reaction. For the next step, we propose a one-step two-electron redox reaction between L and Ru~(IV) under anaerobic conditions, which differentiates from Clarke’s mechanism of two consecutive one-electron redox reactions between L, Ru~(III), and O_2.
机译:通过紫外-可见光谱,液相色谱法研究了碱性溶液中脱氧肌苷(dIno)和黄嘌呤(Xao)的五氨合钌(III)络合物[[Ru〜(III)(NH_3)_5(L)],L为dIno,Xao)。 /电喷雾电离质谱和高效液相色谱。两种Ru〜(III)配合物均与Ru〜(II)和RuIV不成比例。歧化遵循速率定律d [Ru〜(II)] / dt =(k_o + k_1 [OH〜-])[Ru〜(III)]。 [Ru]在25°C时歧化的k_o和k_1分别为2.1(±0.1)9 10〜(-3)s〜(-1)和21.4±3.2 M〜(-1)s〜(-1) 〜(III)(NH_3)_5(dIno)]和3.5(±0.7)9 ​​10〜(-4)s〜(-1)和59.7±3.6 M〜(-1)s〜(-1)对于[Ru〜(III)(NH_3)_5(Xao)]。由于Xao中环外氧的较强吸电子作用,[Ru〜(III)(NH_3)_5(Xao)]络合物的分布速度比[Ru〜(III)(NH_3)_5(dIno)]更快。激活参数ΔH〜?和ΔS〜? [Ru〜(III)(NH_3)_5(dIno)]的k_1分别为80.2±15.2 kJ mol〜(-1)和47.6±9.8 JK〜(-1)mol〜(-1),表明由于活化的正熵,有利于Ru〜(III)与Ru〜(II)和RuIV的歧化。比较了在Ar下碱性溶液中两种络合物的最终产物与在O_2下的最终产物。在两种条件下都产生了[Ru(NH_3)_5(8-oxo-L)],但机制不同。在有氧和无氧条件下,Ru-L的高度正极化的C8-H被OH〜-脱质子,都会引发两电子氧化还原反应。下一步,我们建议在厌氧条件下,L和Ru〜(IV)之间进行一步电子双氧化还原反应,这与Clarke在L,Ru〜(III)之间连续进行两次电子单氧化还原反应的机理不同。和O_2。

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