首页> 外文期刊>The Journal of Chemical Physics >Intrinsic reaction coordinate analysis of the conversion of methane to methanol by an iron-oxo species: A study of crossing seams of potential energy surfaces
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Intrinsic reaction coordinate analysis of the conversion of methane to methanol by an iron-oxo species: A study of crossing seams of potential energy surfaces

机译:铁-氧代甲烷将甲烷转化为甲醇的本征反应坐标分析:势能面交叉缝的研究

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Crossing seams between the potential energy surfaces and possible spin inversion processes for the direct conversion of methane to methanol by the bare FeO~+ species are discussed by means of the intrinsic reaction coordinate (IRC) approach. There are three crossing seams between the sextet and the quartet potential energy surfaces, and spin inversion should occur twice in the entrance and the exit channels; FeO~+(~6sum~+) + CH_4(~1A_1) -> OFe~+(CH_4)(~6A) -> TSl(~4A') -> HO-Fe~+-CH_3(~4A) -> TS2 (~4A) -> Fe~+(CH_3OH)(~4A) -> Fe~+(~6D) + CH_3OH(~1A'). The first crossing seam exists in prior to TSl, a four-centered transition state for the cleavage of a C-H bond of methane. This crossing seam is the most important aspect in this reaction pathway because the molecular system should change its spin multiplicity from the sextet state to the quartet state near this crossing region, leading to a significant decrease in the barrier height of TSl from 31.1 to 22.1 kcal/mol at the B3LYP level of density function theory. The second crossing seam occurs in the vicinity of the hydroxy intermediate (HO-Fe~+-Ch_3), but this crossing seam would not play a significant role because the quartet IRC valley always lies below the sextet one in this region of reaction coordinate and accordingly the molecular system would preferentially move on the quartet potential energy surface. The third crossing seam exists in exit channel in which the elimination of methanol occurs from the product complex. This crossing seam will again lead to spin inversion from the quartet to the sextet state, by which the elimination energy can be decreased from 57.2 to 37.4 kcal/mol in the FeO~+/CH_4 system.
机译:借助内在反应坐标(IRC)方法,讨论了势能表面之间的交叉接缝和可能的光解转化过程,以将裸露的FeO〜+物种直接将甲烷转化为甲醇。在六重奏和四重奏的势能面之间有三个交叉的接缝,自旋反转应在入口和出口通道中发生两次。 FeO〜+(〜6sum〜+)+ CH_4(〜1A_1)-> OFe〜+(CH_4)(〜6A)-> TSl(〜4A')-> HO-Fe〜+ -CH_3(〜4A)-> TS2(〜4A)-> Fe〜+(CH_3OH)(〜4A)-> Fe〜+(〜6D)+ CH_3OH(〜1A')。第一交叉接缝存在于TS1之前,其为用于裂解甲烷的C-H键的四中心过渡态。该交叉接缝是该反应路径中最重要的方面,因为分子系统应在此交叉区域附近将其自旋多重性从六重态改变为四重态,从而导致TS1的势垒高度从31.1 kcal显着降低至22.1 kcal / mol在密度函数理论的B3LYP级别。第二个交叉接缝发生在羟基中间体(HO-Fe〜+ -Ch_3)附近,但是该交叉接缝不会发挥重要作用,因为四重体IRC谷在该反应坐标和该区域始终位于六边形之下。因此,分子系统将优先在四方势能表面上移动。第三交叉接缝存在于出口通道中,在该出口通道中从产物络合物中消除了甲醇。该交叉接缝将再次导致自四重态旋转成六重态,从而在FeO〜+ / CH_4系统中消除能从57.2 kcal / mol降低至37.4 kcal / mol。

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