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首页> 外文期刊>Protein Engineering >FOLDING AND CONFORMATIONAL STUDIES ON SCR1-3 DOMAINS OF HUMAN COMPLEMENT RECEPTOR 1
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FOLDING AND CONFORMATIONAL STUDIES ON SCR1-3 DOMAINS OF HUMAN COMPLEMENT RECEPTOR 1

机译:人补体受体1的SCR1-3区的折叠和构象研究

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Short consensus repeats SCR3 and SCR1-3 are soluble recombinant proteins, consisting of the third and first three N-terminal domains of complement receptor 1, respectively, which retain some anti-complement activity, The conformational stabilities and folding/unfolding of SCR3 and SCR1-3 have been studied using circular dichroism and equilibrium and pre-equilibrium fluorescence spectroscopy, Denaturation by guanidinium hydrochloride (GdnHCl) is rapid and completely reversible, Reduction of disulphide bridges in the folded proteins by P-mercaptoethanol leads to an increase in fluorescence intensity, The fluorescence intensity of the folded proteins is similar to 7.5% of that of the respective unfolded proteins, The data can be approximated to a two-state transition between native and denatured forms of the proteins, SCR3 has a conformational stability in water of 12-13 kJ/mol whereas that of SCR1-3 is 19.5-19.9 kJ/mol depending upon the technique utilized, The heat capacity change associated with the unfolding of SCR1-3 was obtained by a series of GdnHCl unfolding experiments over a range of temperatures and was found to be 6.6 kJ/K,mol or 33.8 J/K.mol(residue). The refolding process of SCR3 was found to be simple, described by a single exponential equation, whereas that of SCR1-3 was found to be complex and could be fitted to a double exponential equation indicating the presence of folding intermediates. [References: 24]
机译:短共有重复序列SCR3和SCR1-3是可溶性重组蛋白,分别由补体受体1的第三个和第三个N末端结构域组成,它们保留了一些抗补体活性,SCR3和SCR1的构象稳定性和折叠/解折叠-3已使用圆二色性和平衡以及平衡前的荧光光谱进行了研究,盐酸胍(GdnHCl)的变性快速且完全可逆,P-巯基乙醇还原折叠蛋白中的二硫键导致荧光强度增加,折叠后的蛋白质的荧光强度约为相应未折叠蛋白质的7.5%。数据可以近似为蛋白质的天然形式和变性形式之间的两态过渡,SCR3在水中的构象稳定性为12- 13 kJ / mol,而SCR1-3则为19.5-19.9 kJ / mol,具体取决于所使用的技术。通过一系列GdnHCl在一定温度范围内的展开实验获得了与SCR1-3展开相同的结果,结果发现其为6.6 kJ / K,mol或33.8 J / K.mol(残基)。发现SCR3的重折叠过程很简单,用一个指数方程式描述,而SCR1-3的重折叠过程则很复杂,可以拟合为表示折叠中间体存在的双指数方程式。 [参考:24]

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