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Hereditarily supercompact spaces

机译:遗传超紧凑空间

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摘要

A topological space X is called hereditarily supercompact if each closed subspace of X is supercompact. By a combined result of Bula, Nikiel, Tuncali, Tymchatyn, and Rudin, each monotonically normal compact Hausdorff space is hereditarily supercompact. A dyadic compact space is hereditarily supercompact if and only if it is metrizable. Under (MA+CH) each separable hereditarily supercompact space is hereditarily separable and hereditarily Lindelof. This implies that under (MA+CH) a scattered compact space is metrizable if and only if it is separable and hereditarily supercompact. The hereditary supercompactness is not productive: the product [0,1] × αD of the closed interval and the one-point compactification aD of a discrete space D of cardinality |D| ≥ non(M) is not hereditarily supercompact (but is Rosenthal compact and uniform Eberlein compact). Moreover, under the assumption cof(M) = ω_1 the space [0,1] × αD contains a closed subspace X which is first countable and hereditarily paracompact but not supercompact.
机译:如果X的每个封闭子空间都是超紧缩的,则拓扑空间X称为遗传超紧缩。通过Bula,Nikiel,Tuncali,Tymchatyn和Rudin的组合结果,每个单调正常紧致的Hausdorff空间都具有遗传上的超紧凑性。当且仅当二元紧致空间是可量化的时,它才是遗传超紧凑的。在(MA + CH)下,每个可分离的遗传上的超紧凑空间都是可遗传的和遗传上的Lindelof。这意味着在(MA + CH)下,当且仅当它是可分离且遗传上超紧凑的时,分散的紧凑空间才是可度量的。遗传的超紧凑性不起作用:闭合区间的乘积[0,1]×αD与基数离散空间D的单点压缩aD | D |。 ≥non(M)不是遗传上的超紧凑型(但是Rosenthal紧密型和均匀Eberlein紧密型)。此外,在假设cof(M)=ω_1的情况下,空间[0,1]×αD包含一个封闭的子空间X,该子空间X首先是可数的并且遗传上是超紧缩的,而不是超紧缩的。

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