首页> 外文期刊>Theory of computing systems >A Combinatorial Analysis for the Critical Clause Tree
【24h】

A Combinatorial Analysis for the Critical Clause Tree

机译:关键子句树的组合分析

获取原文
获取原文并翻译 | 示例
       

摘要

In Paturi, Pudlak, Saks, and Zane (Proceedings of the 39th Annual IEEE Symposium on Foundations of Computer Science (FOCS1998), pp. 628-637, 1998) proposed a simple randomized algorithm for finding a satisfying assignment of a k-CNF formula. The main lemma of the paper is as follows: Given a satisfiable k-CNF formula that has a d-isolated satisfying assignment z, the randomized algorithm finds z with probability at least 2~(-(1-μk/(k-1)+∈k(d))n), where μk/(k - 1) = ∑_(i=1)~∞1/(i((k-1)i+1)), and ∈k(d) = od(1). They estimated the lower bound of the probability in an analytical way, and used some asymptotics. In this paper, we analyze the same randomized algorithm, and estimate the probability in a combinatorial way. The lower bound we obtain is a little simpler: 2~(-(1-μk(d)/(k-1))n), where μk(d)/(k - 1) =∑_(i=1)~d1/(i((k-1)i+1)). This value is a little bit larger (i.e., better) than that of Paturi et al. (Proceedings of the 39th Annual IEEE Symposium on Foundations of Computer Science (FOCS1998), pp. 628-637,1998) although the two values are asymptotically equal when d = ω(1).
机译:在Paturi中,Pudlak,Saks和Zane(第39届IEEE计算机科学基础年度研讨会论文集(FOCS1998),第628-637页,1998年)提出了一种简单的随机算法,用于寻找令人满意的k-CNF公式分配。本文的主要问题如下:给定一个满足d隔离且满足z的可满足k-CNF公式,随机算法发现z的概率至少为2〜(-(1-μk/(k-1) +∈k(d))n),其中μk/(k-1)= ∑_(i = 1)〜∞1/(i((k-1)i + 1))和∈k(d) = od(1)。他们以分析的方式估计了概率的下限,并使用了一些渐近线。在本文中,我们分析了相同的随机算法,并以组合方式估计了概率。我们获得的下界更简单一些:2〜(-(1-μk(d)/(k-1))n),其中μk(d)/(k-1)= ∑_(i = 1) 〜d1 /(i((k-1)i + 1))。该值比Paturi等人的值大一点(即更好)。 (第39届IEEE计算机科学基础年度研讨会论文集(FOCS1998),第628-637页,1998年),尽管当d =ω(1)时,两个值渐近相等。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号