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The geometry of inadmissibility of independent observations for estimating a single parameter in two-parameter ordered symmetric problems

机译:用于估计两参数有序对称问题中的单个参数的独立观测值的不可接受几何

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We consider settings where: (ⅰ) from one "primary" study we obtain an observation from a continuous symmetric distribution, and where the goal is to estimate the center of symmetry with absolute loss; (ⅱ) from a second study, we are aware of an independent observation from a symmetric distribution with the same shape as in the first study, but with a possibly different center of symmetry; and (ⅲ) we know the order of the two centers, but not their values. Practically, the two observations can be estimators of the locations, obtained separately from the two studies; the symmetry can be arising from the central limit behaviour of the estimators, and the known order often arises (e.g., in public health or medicine) from knowledge of the types of populations studied. In the literature, this problem has been dealt algebraically, and most often with combination of losses across parameters. In this paper we provide a geometric proof that, in order to estimate even only the location for the first "primary" population with absolute loss, without combining losses with the second population, the first observation alone is inadmissible in the presence of the second independent observation from the different unknown location. The geometric result provides a fresh understanding of the problem and its practical implications.
机译:我们考虑以下情况:(ⅰ)从一项“主要”研究中,我们从连续的对称分布中获得观测值,并且目标是估计具有绝对损耗的对称中心; (ⅱ)在第二项研究中,我们意识到从对称分布获得的独立观察结果与第一项研究中的形状相同,但对称中心可能不同; (ⅲ)我们知道两个中心的顺序,但不知道它们的值。实际上,这两个观测值可以作为位置的估计量,可以从这两个研究中分别获得。对称性可能是由估算器的中心极限行为引起的,而已知顺序通常是由对所研究人群类型的了解而产生的(例如,在公共卫生或医学领域)。在文献中,这个问题已经通过代数方式解决,并且最常见的是跨参数损失的组合。在本文中,我们提供了一个几何证明,即为了仅估计绝对损失的第一个“主要”种群的位置,而又不将损失与第二个种群相结合,在存在第二个独立种群的情况下,仅第一个观察结果是不可接受的从不同的未知位置进行观察。几何结果提供了对该问题及其实际含义的新鲜理解。

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