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首页> 外文期刊>Mathematical structures in computer science >The sequential topology on N~(N~N) is not regular
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The sequential topology on N~(N~N) is not regular

机译:N〜(N〜N)上的顺序拓扑不规则

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The compact-open topology on the set of continuous functionals from the Baire space to the natural numbers is well known to be zero-dimensional. We prove that the closely related sequential topology on this set is not even regular. The sequential topology arises naturally as the topology carried by the exponential N~((N~N)) formed in various cartesian closed categories of topological spaces. Moreover, we give an example of an effectively open subset of N~((N~N)) that violates regularity. The topological properties of N~((N~N)) are known to be closely related to an open problem in Computable Analysis. We also show that the sequential topology on the space of continuous real-valued functions on a Polish space need not be regular.
机译:众所周知,从Baire空间到自然数的连续函数集上的紧凑开放拓扑是零维的。我们证明了在这个集合上紧密相关的顺序拓扑甚至不是规则的。顺序拓扑自然是由拓扑空间中各种笛卡尔封闭类别中形成的指数N〜((N〜N))所承载的拓扑自然而然地出现的。此外,我们给出了一个违反规则性的有效开放子集N〜((N〜N))的示例。已知N〜((N〜N))的拓扑性质与可计算分析中的开放问题密切相关。我们还表明,波兰空间上连续实值函数空间上的顺序拓扑不需要规则。

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