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On the gap between the quadratic integer programming problem and its semidefinite relaxation

机译:关于二次整数规划问题与其半定松弛之间的差距

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摘要

Consider the semidefinite relaxation (SDR) of the quadratic integer program (QIP): where Q is a given symmetric matrix and D is diagonal. We consider the SDR gap We establish the uniqueness of the SDR solution and prove that if and only if γ r :=n −1max{x T VV T x:x ∈ {-1, 1} n }=1 where V is an orthogonal matrix whose columns span the (r–dimensional) null space of D−Q and where D is the unique SDR solution. We also give a test for establishing whether that involves 2 r −1 function evaluations. In the case that γ r <1 we derive an upper bound on γ which is tighter than Thus we show that `breaching' the SDR gap for the QIP problem is as difficult as the solution of a QIP with the rank of the cost function matrix equal to the dimension of the null space of D−Q. This reduced rank QIP problem has been recently shown to be solvable in polynomial time for fixed r.
机译:考虑二次整数程序(QIP)的半定松弛(SDR):其中Q是给定的对称矩阵,D是对角线。考虑SDR差距我们建立SDR解决方案的唯一性,并证明只有当γr := n -1 max {x T VV T x :x∈{-1,1} n } = 1其中V是一个正交矩阵,其列跨越DQ的(r维)零空间,而D是唯一的SDR解决方案。我们还进行了一项测试,以确定是否涉及2 r -1 函数评估。在γr <1的情况下,我们得出γ的上限更紧。因此,我们证明了“突破” QIP问题的SDR差距与解决等级为QIP的QIP一样困难。成本函数矩阵等于DQ的零空间的维数。对于固定的r,最近已证明该降低秩的QIP问题可以在多项式时间内解决。

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