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首页> 外文期刊>Journal of Solution Chemistry >Thermodynamic Model for SnO2(cr) and SnO2(am) Solubility in the Aqueous Na+–H+–OH−–Cl−–H2O System
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Thermodynamic Model for SnO2(cr) and SnO2(am) Solubility in the Aqueous Na+–H+–OH−–Cl−–H2O System

机译:SnO2 (cr)和SnO2 (am)在Na + –H + –OH- –Cl − –中的溶解度热力学模型H2 O系统

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摘要

The solubility of SnO2(cassiterite) was studied at 23±2 °C as a function of time (7 to 49 days) and pH (0 to 14.5). Steady state concentrations were reached in 7 days. The data were interpreted using the SIT model. The data show that SnO2(cassiterite) is the stable phase at pH values of ∼11.7. These extensive data provided a log 10 K 0 value of −64.39±0.30 for the reaction (SnO2(cassiterite) +2H2O⇄Sn4++4OH−) and values of 1.86±0.30, ≤−0.62, −9.20±0.34, and −20.28±0.34 for the reaction ( $mathrm{Sn}^{4+} + nmathrm{H}_{2}mathrm{O} rightleftarrows mathrm{Sn}(mathrm{OH})_{n}^{4 - n} + nmathrm{H}^{+}$ ) with values of “n” equal to 1, 4, 5, and 6 respectively. These thermodynamic hydrolysis constants were used to reinterpret the extensive literature data for SnO2(am) solubility, which provided a log 10 K 0 value of −61.80±0.29 for the reaction (SnO2(am)+2H2O⇄Sn4++4OH−). SnO2(cassiterite) is unstable under highly alkaline conditions (NaOH concentrations 0.003 mol⋅dm−3) and transforms to a double salt of SnO2 and NaOH. Although additional well-focused studies will be required for confirmation, the experimental data in the highly alkaline region (0.003 to 3.5 mol⋅dm−3 NaOH) can be well described with log 10 K 0 of −5.29±0.35 for the reaction Na2Sn(OH)6(s)⇄Na2Sn(OH)6(aq).
机译:研究了SnO2(锡石)在23±2°C下的溶解度随时间(7至49天)和pH(0至14.5)的变化。在不到7天的时间内达到稳态浓度。使用SIT模型解释数据。数据表明SnO2 (锡石)在pH值≤11.7时是稳定相。这些大量数据为反应(SnO2 (锡石)+ 2H2 O⇄Sn4+ + 4OH)的log 10 K 0 值提供了−64.39±0.30的对数。 -),并且对于该反应($ mathrm {Sn} ^ {4+} + nmathrm {H} _ {2},值应为1.86±0.30,≤−0.62,−9.20±0.34和−20.28±0.34 mathrm {O} rightleftarrows mathrm {Sn}(mathrm {OH})_ {n} ^ {4-n} + nmathrm {H} ^ {+} $),其“ n”值等于1、4、5和6。这些热力学水解常数用于重新解释SnO2 (am)溶解度的大量文献数据,该数据为反应提供了log61 K 0 值-61.80±0.29(SnO2 < / sub>(am)+ 2H2 O⇄Sn4+ + 4OH-)。 SnO2 (锡石)在高碱性条件下(NaOH浓度> 0.003 mol·dm-3 )不稳定,并转化为SnO2 和NaOH的复盐。尽管还需要进行更多的重点研究来确认,但是在高碱性区域(0.003至3.5 mol·dm-3 NaOH)的实验数据可以用log 10 K 0很好地描述。 Na2 Sn(OH)6 (s)⇄Na2 Sn(OH)6 (aq)反应的−5.29±0.35的sup>。

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