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Experimental and theoretical studies on radical trifluoromethylation of titanium ate and lithium enolates

机译:钛酸酯和烯醇锂自由基三氟甲基化的实验和理论研究

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The radical trifluoromethylation of Ti ate and Li enolates has been investigated by both experiments and density functional (UB3LYP/6-311+G*//UB3LYP/6-31+G*) calculations. Radical CF3 addition to the enolates proceeds in a highly exothermic manner without significant reaction barriers in both Ti ate and Li enolates. There are two possible reaction paths after the addition of CF3 radical in the case of Ti ate enolate; one is the elimination of Ti(III) from the ketyl radical intermediate and the other is the direct reaction of the ketyl radical intermediate with CF3I. However, in the case of Li enolate, only the latter path is possible due to the high energy barrier of the elimination of the Li radical. This analysis provides an explanation of the experimental observation that the Li enolate could form the radical cycle efficiently but the Ti ate enolate could not. To make the radical cycle complete, I- has to be extracted from CF3I itself or the radical anion of CF3I. In the case of Li, formation of Li-I bond could be the driving force for the extraction of I- and regeneration of CF3 radical. However, Ti does not give exothermic Ti-I formation and thus regeneration of CF3 radical is less likely.
机译:通过实验和密度泛函(UB3LYP / 6-311 + G * // UB3LYP / 6-31 + G *)计算,研究了钛酸酯和锂烯酸酯的自由基三氟甲基化。自由基CF3向烯醇化物中的添加以高度放热的方式进行,而钛酸酯和锂烯醇化物均无明显反应障碍。在钛酸酯烯酸酯的情况下,添加CF 3自由基后有两种可能的反应路径。一种是从酮基中间体中消除Ti(III),另一种是酮基中间体与CF3I的直接反应。然而,在烯醇化锂的情况下,由于消除锂自由基的高能垒,只有后者是可行的。该分析为实验观察的解释提供了解释,即烯醇锂可以有效地形成自由基循环,而钛酸酯烯醇则不能。为了使自由基循环完成,必须从CF3I本身或CF3I的自由基阴离子中提取I-。对于Li,Li-I键的形成可能是I-提取和CF3自由基再生的驱动力。但是,Ti不会产生放热的Ti-I生成,因此CF3自由基的再生可能性较小。

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