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Crystal structure of sibirskite (CaHBO_3) by Monte Carlo simulation and Rietveld refinement

机译:蒙特卡罗模拟和Rietveld精炼法制备方解石(CaHBO_3)的晶体结构

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摘要

The crystal structure of sibirskite (CaHBO_3) was solved by the Monte Carlo simulation using powder X-ray diffraction data and confirmed by the Rietveld refinement. The mineral sibirskite is monoclinic with space group P2_1/a and cell constants of a = 8.643(6), b = 9.523(2), c = 3.567(3) A, and β = 119.23(3)°. The unit cell consists of independent atoms such as calcium, boron, hydrogen, and three oxygen atoms. The calcium atom is surrounded by six oxygen atoms in an octahedral coordination, and a symmetrical pair of edge-shared CaO_6, octa-hedra forming a double chain elongates the crystallographic c axis. The CaO_6, double chains are not directly connected to each other. The BO_3 triangles are linked to one vertical and two shared oxygen atoms in three CaO_6 double chains to form the sibirskite structure. Sibirskite is isostructural with nahcolite (NaHCO_3), which consists of NaO_6 double chains and CO_3 triangles.
机译:利用粉末X射线衍射数据通过蒙特卡洛模拟对方解石(CaHBO_3)的晶体结构进行了解析,并通过Rietveld精炼法进行了证实。矿物白云母为单斜晶,空间群为P2_1 / a,晶胞常数为a = 8.643(6),b = 9.523(2),c = 3.567(3)A和β= 119.23(3)°。晶胞由独立的原子组成,例如钙,硼,氢和三个氧原子。钙原子在八面体配位中被六个氧原子包围,对称的一对边缘共享的CaO_6(形成双链的八面体)延长了晶体学c轴。 CaO_6,双链不直接彼此连接。 BO_3三角形与三个CaO_6双链中的一个垂直和两个共享的氧原子相连,形成了方钠石结构。西伯利亚石与纳科石(NaHCO_3)是同构的,后者由NaO_6双链和CO_3三角形组成。

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