...
首页> 外文期刊>Journal of Mathematical Sciences >ON THE PROPERTY D(2) AND A COMMON SPLITTING FIELD OF TWO BIQUATERNION ALGEBRAS
【24h】

ON THE PROPERTY D(2) AND A COMMON SPLITTING FIELD OF TWO BIQUATERNION ALGEBRAS

机译:两个双四级数代数的性质D(2)和一个公共裂域

获取原文
获取原文并翻译 | 示例

摘要

Let F be a field of characteristic ≠ 2. We say that F possesses the property D(2) if for any quadratic extension L/F and any two binary quadratic forms over F having a common nonzero value over L, this value can be chosen in F. There exist examples of fields of characteristic 0 that do not satisfy the property D(2). However, as far as we know, it is still unknown whether there are such examples of positive characteristic and what is the minimal 2-cohomological dimension of fields for which the property D{2) does not hold. In this note it is shown that if k is a field of characteristic ≠ 2 such that ∣k~*/k~(*2)∣ ≥ 4, then for the field k(x) the property D(2) does not hold. Using this fact, we construct two biquaternion algebras over a field K = k(x)((t))((u)) such that their sum is a quaternion algebra, but they do not have a common biquadratic (i.e., a field of the kind K(a~(1/2),b~(1/2)), where a, b ∈ K~*) splitting field.
机译:令F为特征≠2的字段。如果对于任意二次扩展L / F和F上的任意两个二进制二次形式在L上具有非零值,则F拥有属性D(2)。在F中。存在特征0的字段不满足属性D(2)的示例。但是,据我们所知,尚不存在这样的正特性示例,以及不具有属性D {2)的场的最小2-同调维数。在该注释中表明,如果k是特征≠2的字段,使得∣k〜* / k〜(* 2)∣≥4,则对于字段k(x),属性D(2)不成立。利用这一事实,我们在场K = k(x)((t))((u))上构造了两个双四元数代数,使得它们的和是四元数代数,但是它们没有共同的双二元数(即,一个场)类型为K(a〜(1/2),b〜(1/2)),其中a,b∈K〜*)分裂场。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号