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Punch problem for piezoelectric ceramic half-plane

机译:压电陶瓷半平面的打孔问题

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Based on the theory of linear piezoelectricity, this study presents an exact solution for a two dimensional indentation on a piezoelectric ceramic half-plane with different contact conditions. The flat-ended indenters are assumed to be rigid. Besides, they can either be insulating or conducting. In addition, different contact conditions, including frictionless, frictional, and adhesive punches are investigated. Lekhnitskii's formulism and Fourier transforms are used to obtain the Green's function of a piezoelectric ceramic half-plane subjected to a point loading. Utilizing Green's half-plane function, we obtain the three integral equations by connecting generalized displacement gradients at the surface and surface loading. Both uncoupled and coupled integral equations can be transformed into a Fredholm integral equation. The analytical closed form solutions of the contact forces and the electric charges under the indenter can be derived by solving the Fredholm integral equations. Once the distributions of the contact forces and the electric charges on the surface are known, the electroelastic response in the half-plane can also be obtained.View full textDownload full textKeywordspunch, piezoelectric ceramics, Fredholm integral equation, indenterRelated var addthis_config = { ui_cobrand: "Taylor & Francis Online", services_compact: "citeulike,netvibes,twitter,technorati,delicious,linkedin,facebook,stumbleupon,digg,google,more", pubid: "ra-4dff56cd6bb1830b" }; Add to shortlist Link Permalink http://dx.doi.org/10.1080/02533839.2011.591961
机译:基于线性压电理论,本研究为具有不同接触条件的压电陶瓷半平面上的二维压痕提供了精确的解决方案。假定平端压头是刚性的。此外,它们可以绝缘或导电。此外,还研究了不同的接触条件,包括无摩擦冲头,摩擦冲头和粘合冲头。 Lekhnitskii的公式和傅里叶变换用于获得承受点载荷的压电陶瓷半平面的格林函数。利用格林的半平面函数,我们通过连接表面和表面载荷下的广义位移梯度获得三个积分方程。解耦积分方程和耦合积分方程都可以转换为Fredholm积分方程。压头下接触力和电荷的解析闭合形式解可以通过求解Fredholm积分方程得出。一旦知道了表面上的接触力和电荷的分布,就可以得到半平面的电弹性响应。查看全文下载全文关键词冲压,压电陶瓷,Fredholm积分方程,indenterRelated var addthis_config = {ui_cobrand: “泰勒和弗朗西斯在线”,services_compact:“ citeulike,netvibes,twitter,technorati,delicious,linkedin,facebook,stumbleupon,digg,google,更多”,发布:“ ra-4dff56cd6bb1830b”};添加到候选列表链接永久链接http://dx.doi.org/10.1080/02533839.2011.591961

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