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On the linear assignment problem for special matrices

机译:关于特殊矩阵的线性分配问题

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This study arises from the intersection of two application areas of management mathematics and control theory: the assignment problem and the theory of discrete-event dynamic systems (DEDS), The assignment problem is to find the cheapest one-to-one pairing between two sets (e.g. machines and operators), given a matrix (a_(ij)) of the cost of pairing the z'th machine with the jth operator. A DEDS is a system such as certain manufacturing, transportation or data-processing systems, which move from event to event in discrete steps. The realization problem for such a DEDS is that of deducing its possible structure on the basis of a stream of observations, g_0, g_1,..., known as Markov parameters. The structure is expressed in a linear-algebraic model known as a realization and for economy a realization of minimal dimension (MDR) is sought. For certain DEDS, it is convenient to work in max-algebra, in which the classsical operations of addition and multiplication are replaced by the operations max and +, respectively. Establishing a lower bound for the dimension of an MDR then turns on finding the structure of the optimal solution set of an assignment problem whose cost matrix is a Hankel matrix. This is connected to a known hard combinatorial problem and does not seem to be solved for Hankel matrices in general. However, the paper shows that a straightforward solution exists in two special cases, when the sequence {g_r} is either convex or concave.
机译:该研究源于管理数学和控制理论两个应用领域的交叉:分配问题和离散事件动态系统理论(DEDS),分配问题是找到两组之间最便宜的一对一配对(例如机器和运算符),给出将第z个机器与第j个运算符配对的成本的矩阵(a_(ij))。 DEDS是诸如某些制造,运输或数据处理系统之类的系统,它们在事件之间以离散的步骤移动。这种DEDS的实现问题在于,基于已知的马尔可夫参数观测流g_0,g_1 ...推导出其可能的结构。该结构以称为实现的线性代数模型表示,为经济起见,寻求最小尺寸(MDR)的实现。对于某些DEDS,在max-algebra中工作是很方便的,在其中maxmax和+分别替换了加法和乘法的经典运算。为MDR的维数确定下界,然后打开寻找其成本矩阵为汉克尔矩阵的分配问题的最优解集的结构。这与已知的硬组合问题有关,通常对于汉克矩阵似乎无法解决。但是,本文表明,当序列{g_r}是凸的或凹的时,在两种特殊情况下都存在一种简单的解决方案。

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