首页> 外文期刊>Distributed Computing >Beeping a maximal independent set
【24h】

Beeping a maximal independent set

机译:蜂鸣最大独立集

获取原文
获取原文并翻译 | 示例
           

摘要

We consider the problem of computing a maximal independent set (MIS) in an extremely harsh broadcast model that relies only on carrier sensing. The model consists of an anonymous broadcast network in which nodes have no knowledge about the topology of the network or even an upper bound on its size. Furthermore, it is assumed that an adversary chooses at which time slot each node wakes up. At each time slot a node can either beep, that is, emit a signal, or be silent. At a particular time slot, beeping nodes receive no feedback, while silent nodes can only differentiate between none of its neighbors beeping, or at least one of its neighbors beeping. We start by proving a lower bound that shows that in this model, it is not possible to locally converge to an MIS in sub-polynomial time. We then study four different relaxations of the model which allow us to circumvent the lower bound and find an MIS in polylogarithmic time. First, we show that if a polynomial upper bound on the network size is known, it is possible to find an MIS in (mathcal O (log ^3 n)) time. Second, if we assume sleeping nodes are awoken by neighboring beeps, then we can also find an MIS in (mathcal O (log ^3 n)) time. Third, if in addition to this wakeup assumption we allow sender-side collision detection, that is, beeping nodes can distinguish whether at least one neighboring node is beeping concurrently or not, we can find an MIS in (mathcal O (log ^2 n)) time. Finally, if instead we endow nodes with synchronous clocks, it is also possible to find an MIS in (mathcal O (log ^2 n)) time.
机译:我们考虑在极其苛刻的广播模型中仅依赖载波侦听来计算最大独立集(MIS)的问题。该模型由一个匿名广播网络组成,该网络中的节点不了解网络的拓扑,甚至不知道其大小的上限。此外,假设对手选择每个节点在哪个时隙唤醒。在每个时隙,节点可以发出哔声,即发出信号,也可以保持沉默。在特定时隙,蜂鸣节点不会收到任何反馈,而静默节点只能区分其邻居之间没有蜂鸣,或者邻居之间至少有一个蜂鸣。我们首先证明一个下界,表明该模型在次多项式时间内不可能局部收敛到MIS。然后,我们研究了模型的四个不同松弛,这些松弛使我们能够规避下界并在多对数时间中找到MIS。首先,我们证明如果知道网络大小的多项式上限,则有可能在(数学O(log ^ 3 n))时间内找到一个MIS。其次,如果我们假设睡眠节点被相邻的哔哔声唤醒,那么我们还可以在(数学O(log ^ 3 n))时间内找到一个MIS。第三,如果除了这一唤醒假设之外,我们还允许发送方冲突检测,即蜂鸣节点可以区分是否至少有一个相邻节点正在同时蜂鸣,我们可以在(数学O(log ^ 2 n )) 时间。最后,如果改为给节点赋予同步时钟,则还可以在(数学O(log ^ 2 n))时间内找到一个MIS。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号