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Molecular Evolution of Two Linked Genes, Est-6 and Sod, in Drosophila melanogaster

机译:果蝇中两个相关基因Est-6和Sod的分子进化

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We have obtained 15 sequences of Est-6 from a natural population of Drosophila melanogaster to test whether linkage disequilibrium exists between Est-6 and the closely linked Sod , and whether natural selection may be involved. An early experiment with allozymes had shown linkage disequilibrium between these two loci, while none was detected between other gene pairs. The Sod sequences for the same 15 haplotypes were obtained previously. The two genes exhibit similar levels of nucleotide polymorphism, but the patterns are different. In Est-6 , there are nine amino acid replacement polymorphisms, one of which accounts for the S-F allozyme polymorphism. In Sod , there is only one replacement polymorphism, which corresponds to the S-F allozyme polymorphism. The transversion/transition ratio is more than five times larger in Sod than in Est-6. At the nucleotide level, the S and F alleles of Est-6 make up two allele families that are quite different from each other, while there is relatively little variation within each of them. There are also two families of alleles in Sod , one consisting of a subset of F alleles, and the other consisting of another subset of F alleles, designed F(A), plus all the S alleles. The Sod F(A) and S alleles are completely or nearly identical in nucleotide sequence, except for the replacement mutation that accounts for the allozyme difference. The two allele families have independent evolutionary histories in the two genes. There are traces of statistically significant linkage disequilibrium between the two genes that, we suggest, may have arisen as a consequence of selection favoring one particular sequence at each locus.
机译:我们从果蝇的自然种群中获得了15个Est-6序列,以测试Est-6和紧密相连的Sod之间是否存在连锁不平衡,以及是否可能涉及自然选择。早期的同工酶实验显示这两个基因座之间存在连锁不平衡,而其他基因对之间则未检测到。先前获得了相同15个单倍型的Sod序列。这两个基因表现出相似的核苷酸多态性水平,但是模式却不同。在Est-6中,有9个氨基酸置换多态性,其中之一是S-F同工酶多态性。在Sod中,只有一个替换多态性,它对应于S-F同工酶多态性。草皮的转化/转化比是Est-6的5倍以上。在核苷酸水平上,Est-6的S和F等位基因组成两个彼此完全不同的等位基因家族,而它们之间的变异相对较小。 Sod中也有两个等位基因家族,一个由F等位基因的一个子集组成,另一个由F等位基因的另一个子集(设计为F(A))加上所有S等位基因组成。 Sod F(A)和S等位基因在核苷酸序列上完全或几乎相同,除了替代突变导致了同工酶差异。两个等位基因家族在两个基因中具有独立的进化历史。我们建议在两个基因之间存在统计上显着的连锁不平衡的痕迹,我们认为这可能是由于在每个基因座处选择一个特定序列所致。

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