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首页> 外文期刊>Bulletin of the Korean Chemical Society >Solid State Reactions of Iridium-1,5-Cyclooctadiene Compounds with Hydrogen and Carbon Monoxide
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Solid State Reactions of Iridium-1,5-Cyclooctadiene Compounds with Hydrogen and Carbon Monoxide

机译:1,5-环辛二烯铱化合物与氢和一氧化碳的固相反应

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Solid-gas reactions of [Ir(COD)(PhCN)L]ClO4 (1), [Ir(COD)L2]ClO4 (2), [Ir(H)2(COD)(PhCN)L]ClO4 (3), [Ir(H)2(COD)L2]ClO4 (4), [Ir(COD)(CO)2L]ClO4 (5), [Ir(COD)(CO)L2]ClO4 (6) and [Ir(COD)(PhCN)2]ClO4 (7) (COD=1,5-cyclooctadiene; L=PPh3 (a), AsPh3 (b)) with H2 and CO have been investigated to find the differences in reactivities from those in solution. Ir(H)n moiety and cyclooctene (COE) are detected in the solid-gas reactions of 1 and 2 with H2 while they are not observed in the reactions in solution. Complexes, 3 and 4 lose H2 in the solid state while they undergo hydride transfer to COD in solution to produce COE and cyclooctane (COA). Solid-gas reaction of 5 and 6 with H2 produce only COE at 25∩ while their reactions in solution produce COA. The reaction of CO with 3a in the solid state gives quantitative amount of 5a while in solution it gives only unknown product. Both reactions of 7 in the solid state and in solution with CO give unidentified brown solid which further reacts with CO/H2 to give Ir4(CO)12.
机译:[Ir(COD)(PhCN)L] ClO4(1),[Ir(COD)L2] ClO4(2),[Ir(H)2(COD)(PhCN)L] ClO4(3)的固相反应,[Ir(H)2(COD)L2] ClO4(4),[Ir(COD)(CO)2L] ClO4(5),[Ir(COD)(CO)L2] ClO4(6)和[Ir(研究了COD)(PhCN)2] ClO4(7)(COD = 1,5-环辛二烯; L = PPh3(a),AsPh3(b))与H2和CO的反应活性,以发现其与溶液中的反应性不同。在1和2与H2的固气反应中检测到Ir(H)n部分和环辛烯(COE),而在溶液中的反应中未观察到它们。配合物3和4在固态状态下会损失氢,而它们会通过氢化物转移到溶液中的COD中,从而生成COE和环辛烷(COA)。 5和6与H2的固气反应在25°C时仅产生COE,而它们在溶液中的反应则产生COA。 CO与3a固态反应生成定量5a,而在溶液中仅生成未知产物。固态和与CO溶液中的7的两个反应均产生未鉴定的棕色固体,其进一步与CO / H2反应生成Ir4(CO)12。

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