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Magnetic Susceptibility of Coordination Compounds in the General Chemistry Laboratory

机译:普通化学实验室中配位化合物的磁化率

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A general chemistry laboratory exercise is described in which the number of unpaired electrons in coordination compounds is determined. The compounds are Na2PdCl4, K4Fe(CN)6, Cr(acac)3, Na3FeF6, Co(acac)3 and Mn(acac)2. These compounds are presented to students as Na2PdA4, K4FeA6, CrB3, Na3FeA6, CoB3 and MnB2 respectively where A is monodentate, B is bidentate and both ligands have a charge of ?1. For a coordination number of six an octahedral structure is assumed, and for a coordination number of four, tetrahedral and square planar structures are assumed. After determining the number of d-level electrons, students select applicable energy level diagrams and assign electrons in all possible arrangements consistent with Hund’s rule. Students cross out inappropriate diagrams, providing an explanation for why they have done so. By comparing the number of unpaired electrons determined using magnetic susceptibility and with the remaining diagrams, students deduce the structure and spin arrangement(s) that fit the experimental results. In about half of the cases, the structure is conclusively determined.
机译:描述了一般化学实验室练习,其中确定配位化合物中未配对电子的数量。化合物为Na 2 PdCl 4 ,K 4 Fe(CN) 6 ,Cr(acac) 3 ,Na 3 FeF 6 ,Co(acac) 3 和Mn(acac) 2 >。这些化合物以Na 2 PdA 4 ,K 4 FeA 6 ,CrB 3的形式呈现给学生,Na 3 FeA 6 ,CoB 3 和MnB 2 ,其中A是单齿的,B是双齿的,两个配体的电荷为?1。对于六的配位数,假定八面体结构,对于四的配位数,假设四面体和正方形平面结构。确定 d 级电子数量后,学生选择适用的能级图,并按照与洪德法则相一致的所有可能排列方式分配电子。学生将不适当的图表划掉,并说明为什么这样做。通过比较使用磁化率和其余图表确定的不成对电子的数量,学生可以推断出适合实验结果的结构和自旋排列。在大约一半的情况下,结构是最终确定的。

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