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首页> 外文期刊>South African journal of industrial engineering >SINGLE-MACHINE SCHEDULING OF THE INDIVISIBLE MULTI-OPERATION JOBS
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SINGLE-MACHINE SCHEDULING OF THE INDIVISIBLE MULTI-OPERATION JOBS

机译:不可分割的多操作作业的单机调度

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摘要

This paper considers a single-machine scheduling problem of multi- operation jobs where each job consists of several operations processed contiguously, rather than being intermingled with the operations of different jobs. That is, the jobs are indivisible. A sequence-independent setup is required if the machine switches from one operation to another. However, no setup is necessary before the first operation of a job if this first operation is the same as the last operation of the immediately previous job. A job is complete when all of its operations have been processed. We investigate the problem for two cases. Makespan, which is the time needed to complete all jobs, is minimised in the first case; whereas the total completion time, which is the sum of the job completion times, is minimised in the second case. We show that the makespan problem is solvable in polynomial time. For the problem of minimising total completion time, we develop a mixed integer linear programming (MILP) model, which is capable of solving small and medium-sized problem instances optimally, and obtain a very small gap between the solution found and the best possible solution for the unsolved large-sized problem instances.
机译:本文考虑了多操作作业的单机调度问题,其中每个作业由多个连续处理的操作组成,而不是与不同作业的操作混合在一起。也就是说,工作是不可分割的。如果机器从一种操作切换到另一种操作,则需要与序列无关的设置。但是,如果第一个操作与前一个作业的最后一个操作相同,则无需在作业的第一个操作之前进行任何设置。处理完所有作业后,该作业即告完成。我们针对两个案例调查了该问题。在第一种情况下,最小化完成时间(完成所有工作所需的时间);而在第二种情况下,总的完成时间(即工作完成时间的总和)将最小化。我们证明了makepan问题可以在多项式时间内解决。对于最小化总完成时间的问题,我们开发了一种混合整数线性规划(MILP)模型,该模型能够最佳地解决中小型问题实例,并且在找到的解决方案与可能的最佳解决方案之间获得很小的差距对于未解决的大型问题实例。

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