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The Inconsistency Problem of Riemann Zeta Function Equation

机译:Riemann Zeta函数方程的不一致性问题

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Four basic problems in Riemann's original paper are found. The Riemann hypothesis becomes meaningless. 1. It is proved that on the real axis of complex plane, the Riemann Zeta function equation holds only at point Re(s)=1/2 (s = a+ib). However, at this point, the Zeta function is infinite, rather than zero. At other points of real axis, the two sides of Zeta function equation are contradictory. When one side is finite, another side may be infinite. 2. An integral item around the original point of coordinate system was neglected when Riemann deduced the integral form of Zeta function. The item was convergent when Re(s) 1 but divergent when Re(s) 1. The integral form of Zeta function does not change the divergence of its series form. Two reasons to cause inconsistency and infinite are analyzed. 3. When the integral form of Zeta function was deduced, a summation formula was used. The applicable condition of this formula is x 0. At point x = 0, the formula is meaningless. However, the lower limit of Zeta function integral is x = 0, so the formula can not be used. 4. A formula of Jacobi function was used to prove the symmetry of Zeta function equation. The applicable condition of this formula was also x 0. However, the lower limit of integral in the deduction was x=0. So this formula can not be used too. The zero calculation of Riemann Zeta function is discussed at last. It is pointed out that because approximate methods are used, they are not the real zeros of strict Riemann Zeta function.
机译:在黎曼的原始论文中发现了四个基本问题。黎曼假设变得毫无意义。 1.证明在复平面的实轴上,黎曼Zeta函数方程仅在点Re(s)= 1/2(s = a + ib)成立。但是,此时,Zeta函数是无限的,而不是零。在实轴的其他点,Zeta函数方程的两侧是矛盾的。当一侧是有限的时,另一侧可能是无限的。 2.当Riemann推导Zeta函数的积分形式时,忽略了围绕坐标系原始点的积分项。当Re(s)> 1时该项目收敛,但当Re(s)<1时该项目发散。Zeta函数的积分形式不会改变其级数形式的发散。分析了导致不一致和无限的两个原因。 3.推导Zeta函数的积分形式时,使用求和公式。该公式的适用条件是x>0。在点x = 0处,该公式毫无意义。但是,Zeta函数积分的下限为x = 0,因此无法使用该公式。 4.用雅可比函数公式证明了Zeta函数方程的对称性。该公式的适用条件也是x>0。但是,推论中的积分下限是x = 0。因此,该公式也不能使用。最后讨论了黎曼Zeta函数的零值计算。要指出的是,由于使用了近似方法,因此它们不是严格的黎曼Zeta函数的实零点。

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