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A note on existence and uniqueness for integral equations with sum of two operators: progressive contractions

机译:关于带有两个算子和的积分方程的存在性和唯一性的注记:渐进收缩

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In this note we show a simple way to obtain a unique solution on [0,?∞) of a scalar integral equation where x ,? y ?∈?? and t ?≥?0 imply that ∣ g ( t ,? x )??? g ( t ,? y )∣?≤? α ∣ x ??? y ∣,?0??0 there is a K ?>?0 so that x ,? y ?∈?? and 0?≤? t ?≤? E imply ∣ f ( t ,? x )??? f ( t ,? y )∣?≤? K ∣ x ??? y ∣ .We introduce a progressive contraction .The constant K is a function of E and, hence, may tend to infinity as E ?→?∞ .The conclusion is that there is a single function ξ ( t ) satisfying the equation on [0,?∞) without resorting to any of the classical translations and extensions of solutions which, in fact, must invoke Zorn’s Lemma and which can encounter difficulties as K ?→?∞ .
机译:在本说明中,我们展示了一种简单的方法,可在标量积分方程的[0,?∞)上获得唯一解,其中x,? y?∈??并且t≥≥0意味着∣ g(t,?x)??? g(t,?y)∣?≤? α∣ x ??? y ∣,?0?<? α?<?1,并且对于每个E?>?0,都有一个K?>?0,因此x,? y?∈??和0?≤? t≤ E暗示∣ f(t,?x)??? f(t,?y)∣?≤? K ∣ x ??? y ∣,我们引入了渐进式收缩。常数K是E的函数,因此当E?→?∞时可能趋于无穷大。结论是,存在一个满足[[ 0,?∞)而不求助于解决方案的任何经典翻译和扩展,这些解决方案实际上必须调用Zorn的引理,并且可能会遇到K?→?∞的困难。

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