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首页> 外文期刊>International Journal of Computer Science and Security >Implementation of RSA Algorithm with Chinese Remainder Theorem for Modulus N 1024 Bit and 4096 Bit
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Implementation of RSA Algorithm with Chinese Remainder Theorem for Modulus N 1024 Bit and 4096 Bit

机译:N 1024位和4096位模的中国余数定理RSA算法的实现

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Cryptography has several important aspects in supporting the security of the data, which guarantees confidentiality, integrity and the guarantee of validity (authenticity) data. One of the public-key cryptography is the RSA cryptography. The greater the size of the modulus n, it will be increasingly difficult to factor the value of n. But the flaws in the RSA algorithm is the time required in the decryption process is very long. Theorem used in this research is the Chinese Remainder Theorem (CRT). The goal is to find out how much time it takes RSA-CRT on the size of modulus n 1024 bits and 4096 bits to perform encryption and decryption process and its implementation in Java programming. This implementation is intended as a means of proof of tests performed and generate a cryptographic system with the name "RSA and RSA-CRT Text Security". The results of the testing algorithm is RSA-CRT 1024 bits has a speed of approximately 3 times faster in performing the decryption. In testing the algorithm RSA-CRT 4096 bits, the conclusion that the decryption process is also effective undertaken more rapidly. However, the flaws in the key generation process and the RSA 4096 bits RSA-CRT is that the time needed is longer to generate the keys.
机译:密码学在支持数据安全性方面具有几个重要方面,这些方面可确保机密性,完整性和有效性(真实性)数据的保证。 RSA加密是一种公共密钥加密。模数n的大小越大,将n的值分解就变得越来越困难。但是RSA算法的缺陷是解密过程所需的时间很长。本研究中使用的定理是中国剩余定理(CRT)。目的是找出RSA-CRT在模数n 1024位和4096位的大小上执行加密和解密过程及其在Java编程中的实现所花费的时间。此实现旨在作为执行测试的一种手段,并生成名称为“ RSA and RSA-CRT Text Security”的密码系统。测试算法的结果是RSA-CRT 1024位在执行解密时的速度大约快3倍。在测试RSA-CRT 4096位算法时,解密过程也有效的结论得到了更快的体现。但是,密钥生成过程和RSA 4096位RSA-CRT的缺陷在于生成密钥所需的时间更长。

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