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Showing that the race model inequality is not violated

机译:表明种族模型不平等没有违反

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When participants are asked to respond in the same way to stimuli from different sources (e.g., auditory and visual), responses are often observed to be substantially faster when both stimuli are presented simultaneously (redundancy gain). Different models account for this effect, the two most important being race models and coactivation models. Redundancy gains consistent with the race model have an upper limit, however, which is given by the well-known race model inequality (Miller, 1982). A number of statistical tests have been proposed for testing the race model inequality in single participants and groups of participants. All of these tests use the race model as the null hypothesis, and rejection of the null hypothesis is considered evidence in favor of coactivation. We introduce a statistical test in which the race model prediction is the alternative hypothesis. This test controls the Type I error if a theory predicts that the race model prediction holds in a given experimental condition.
机译:当要求参与者以相同的方式对来自不同来源(例如听觉和视觉)的刺激做出反应时,通常会同时观察到两种刺激(冗余增益)时反应速度明显更快。不同的模型会造成这种影响,其中最重要的两个是种族模型和共同激活模型。然而,与种族模型一致的冗余收益有一个上限,这是由众所周知的种族模型不平等性给出的(Miller,1982)。已经提出了许多统计测试来测试单个参与者和参与者群体中的种族模型不平等。所有这些测试均使用种族模型作为无效假设,并且无效假设的拒绝被视为有利于共激活的证据。我们介绍了一种统计检验,其中种族模型预测是替代假设。如果理论预测种族模型的预测在给定的实验条件下成立,则此测试可控制I型错误。

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