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Electrochemical reduction of ferrous α-verdoheme in complex with heme oxygenase-1

机译:血红素加氧酶-1配合物电化学还原亚铁-verdoheme

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摘要

The heme oxygenase (HO) reaction consists of three successive oxygenation reactions, i.e. heme to α-hydroxyheme, α-hydroxyheme to verdoheme, and verdoheme to biliverdin-iron chelate. Of these, the least understood step is the conversion of verdoheme to biliverdin-iron chelate. For the cleavage of the oxaporphyrin ring of ferrous verdoheme, involvement of a verdoheme π-neutral radical has been proposed. To probe this hypothetical mechanism in the HO reaction, we performed electrochemical reduction of ferrous verdoheme complexed with rat HO-1 under anaerobic conditions. On the basis of the electrochemical spectral changes, the midpoint potential for the one-electron reduction of the oxaporphyrin ring of ferrous verdoheme was found to be −0.47 ± 0.01 V vs the normal hydrogen electrode (NHE). Because this potential is far lower than those of both flavins of NADPH-cytochrome P450 reductase, and of NADPH, it is concluded that the one-electron reduction of the oxaporphyrin ring of ferrous verdoheme is unlikely to occur and that the formation of the π-neutral radical cannot be the initial step in the degradation of verdoheme by HO. Rather, it appears more reasonable to consider an alternative mechanism in which binding of O2 to the ferrous iron of verdoheme is the first step in the degradation of verdoheme.
机译:血红素加氧酶(HO)反应包括三个连续的氧化反应,即血红素变成α-羟基血红素,α-羟基血红素变成verdoheme,以及verdoheme变成biliverdin-铁螯合物。其中,鲜为人知的步骤是Verdoheme转化为Biliverdin-铁螯合物。为了裂解亚铁Verhehe的氧杂卟啉环,提出了Verdohemeπ中性自由基的参与。为了探讨HO反应中的这种假设机制,我们在厌氧条件下对与大鼠HO-1络合的亚铁红血红素进行了电化学还原。根据电化学光谱的变化,对红色六氢亚铁血红素的氧杂卟啉环的单电子还原的中点电势相对于正常氢电极(NHE)为-0.47±0.01V。因为该电势远低于NADPH-细胞色素P450还原酶和NADPH的两种黄素的电势,所以得出的结论是:不太可能发生亚铁Verdoheme的氧磷卟啉环的单电子还原,并且π-中性自由基不能是HO降解Verdoheme的第一步。相反,考虑一种替代机制似乎更合理,在该机制中,O2与Verdoheme的亚铁结合是Verdoheme降解的第一步。

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