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A Clockwork Hypothesis: Synaptic Release by Rod Photoreceptors Must Be Regular

机译:发条假说:杆感光器的突触释放必须规律

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摘要

We can see at light intensities much lower than an average of one photon per rod photoreceptor, demonstrating that rods must be able to transmit a signal after absorption of a single photon. However, activation of one rhodopsin molecule (Rh*) hyperpolarizes a mammalian rod by just 1 mV. Based on the properties of the voltage-dependent Ca2+ channel and data on [Ca2+] in the rod synaptic terminal, the 1 mV hyperpolarization should reduce the rate of release of quanta of neurotransmitter by only ∼20%. If quantal release were Poisson, the distributions of quantal count in the dark and in response to one Rh* would overlap greatly. Depending on the threshold quantal count, the overlap would generate too frequent false positives in the dark, too few true positives in response to one Rh*, or both. Therefore, quantal release must be regular, giving narrower distributions of quantal count that overlap less. We model regular release as an Erlang process, essentially a mechanism that counts many Poisson events before release of a quantum of neurotransmitter. The combination of appropriately narrow distributions of quantal count and a suitable threshold can give few false positives and appropriate (e.g., 35%) efficiency for one Rh*.
机译:我们可以看到,光强度远低于每个棒感光器平均一个光子的强度,这表明棒在吸收单个光子后必须能够传输信号。但是,一个视紫红质分子(Rh *)的激活会使哺乳动物杆超极化1 mV。根据电压依赖性Ca 2 + 通道的特性和杆状突触末端[Ca 2 + ]上的数据,1 mV超极化应降低电导率。神经递质的量子释放仅约20%。如果数量释放是泊松,则在黑暗中和响应一个Rh *时数量计数的分布将大大重叠。取决于阈值的数量,重叠会在黑暗中产生过于频繁的假阳性,对一个Rh *的响应太少的真实阳性,或两者兼而有之。因此,定量释放必须是规则的,从而使较窄的定量分布分布重叠较少。我们将定期释放建模为一个Erlang过程,本质上是一种在释放大量神经递质之前对许多泊松事件进行计数的机制。适当窄的数量计数分布和适当的阈值的组合可以产生很少的假阳性,并且对于一个Rh *而言,具有适当的效率(例如35%)。

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