配合物Ru2(μ-O2CCH3)4(H2O)2PF6的合成、表征及电化学性质

摘要

The title compound, [Ru2 (μ-O2CCH3)4 (H2O)2] PF6, was prepared by treating Ru2 (O2 CCH3)4C1 with methanol aqueous solution at the presence of Ag2SO4 and NH4PF6 through coordinating process. The compound was characterized by elemental analysis, IR spectra, cyclic voltammetry and X-ray single crystal structure analysis. The result reveals that the compound crystallizes in the monoclinic system with space group at C2/c, and a =1. 9 52 3 (9) nm, b = 1. 2 83 0 (6) nm, c =0. 846 8 (4) nm, β=93. 11 (10) and Z = 4. Thermogravimetric analysis was carried out to study the mechanism of thermal decomposition of the complex. The electrochemical property of ruthenium complex were studied by means of cyclic voltametry, the results show that electron transfer between Ru (II) and Ru (III) in electrolysis is quasi-reversible process.%[Ru2(μ-O2CCH3)4(H2O)2]PF6是以Ru2( O2CCH3)4Cl为前体配合物,在甲醇水(体积比7 ∶ 1)溶液中用Ag2SO4和NH4PF6进行脱氯配位反应而得.用元素分析、红外光谱、热重分析、循环伏安、X-衍射单晶结构分析等对其进行表征.晶体结构表明,标题化合物的晶体属单斜晶系,空间群为C2/c,晶胞参数为a=1.9 523 (9) nm,b=1.2830 (6) nm,c=0.8468 (4) nm,β=93.11 (10)°,Z=4.通过热失重分析研究配合物的热分解机理.用循环伏安法对其电化学性质进行表征,结果为一对准可逆的氧化还原峰,表明该配合物的中心金属2价钌原子Ru (Ⅱ)与3价钌原子Ru (Ⅲ)之间存在电子转移.