分拆大偶数为两个几乎相等的素数之和

摘要

We call n=p+q as the most balance Goldbach part it ion for even number n,where p and q are all odd primes,p≤q and |p-q| takes the possible minimal value.According to the Goldbach's conjectur e,there exists the most balance Goldbach partition for every even number greater than or equal to 6.By numerical computation with the even integers not exceedin g 107,we now propose the following conjecture:the means of quotients p/q,p/n ,and (n/2-p)/n　defined by the most balance Goldbac h partitions of all even numbers(≥6)　have the limits 1,1/2,and 0,respectively.%我们称n=p+q为偶数n的最平衡哥德巴赫分拆，其中p 与q均为奇素数，p≤q且|p-q|取可能的最小值。根据哥德巴赫猜想，对于每个大于或等于6的偶数，必存在其最平衡哥德巴赫分拆。本文通过对107以内的偶数进行的数值计算，进一步提出如下猜想：由所有(≥6的)偶数之最平衡哥德巴赫分拆产生的三组比值p/q，p/n以及( n/2-p)/n的均值，分别具有极限1，1/2及0。