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Secondary pyrolysis and combustion of coal volatiles.

机译:煤挥发物的二次热解和燃烧。

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Under rapid heating, pulverized coal releases half of its mass as noncondensibles and high molecular weight tars. The tars are pyrolysed to soot, drastically altering the composition of the noncondensibles. Subsequent combustion of the soot and the fuel species in the noncondensibles causes half the heat release and pollutant formation, and governs the stability of the pulverized coal flame. Even approximate rates for combustion of the volatiles are unknown, but they can be estimated from measurements of the laminar burning velocity.; Laminar burning velocities were measured in a constant volume combustion bomb for the volatiles from an Ill. #6 bituminous and a Dietz subbituminous coal. The volatiles were generated in a radiant flow reactor which had previously been thoroughly characterized for both primary devolatilization and secondary pyrolysis. For volatiles from the Ill. #6 coal, burning velocities triple as the last half of the tar is converted to soot, reaching 150 cm/s at an equivalence ratio of 0.7 in air. The impact of secondary pyrolysis is the same at an increased dilution level. A similar impact of secondary pyrolysis is observed for the volatiles from the Dietz coal, but their burning velocities are about half those from the Ill. #6 for the same conditions.; These tendencies are well described by the following correlation: {dollar}{dollar}rm Ssb{lcub}u{rcub}sp2 = CXsb{lcub}O2{rcub}(Xsb{lcub}H2{rcub} + alpha Xsb{lcub}CH4{rcub})exp({lcub}-{rcub}E/RTsb{lcub}f{rcub}){dollar}{dollar}where the variations of the fuels are represented by the mole fractions of CH{dollar}sb4{dollar} and H{dollar}sb2{dollar}. The equivalence and dilution ratios determine {dollar}rm Xsb{lcub}O2{rcub}{dollar} and the flame temperatures. This equation successfully correlates all of the data for a single coal over wide ranges of both extent of secondary pyrolysis and equivalence ratio. However correlation of the volatiles from the two coals requires different fitting parameters. A modified equation, {dollar}{dollar}rm Ssb{lcub}u{rcub}sp2 = CXsb{lcub}O2{rcub}Xsb{lcub}H2{rcub}Xsb{lcub}CH4{rcub}spalpha Xsb{lcub}CO{rcub}spbeta exp({lcub}-{rcub}E/RTsb{lcub}f{rcub}){dollar}{dollar}successfully correlates all of the data for both coals with a single set of fitting parameters. For the Ill. #6 and Dietz coals of this study, at a reactant temperature and pressure of 430 K and 1 atm, fuel equivalence ratios from 0.4 to 1.1, soot fractions from.5 to 1, and (N{dollar}sb2{dollar}+CO{dollar}sb2{dollar}+H{dollar}sb2{dollar}O)/O{dollar}sb2{dollar} ratios from 3.8 to 6.8, C = 2.7 {dollar}times{dollar} 10{dollar}sp4{dollar} cm{dollar}sp2{dollar}/s{dollar}sp2{dollar}, {dollar}alpha{dollar} = {dollar}-{dollar}1.46, {dollar}beta{dollar} = {dollar}-{dollar}2.69, and E = 52.5 kcal/mole.
机译:在快速加热下,煤粉以不凝性和高分子量焦油形式释放一半的质量。焦油被热解成烟灰,从而极大地改变了非冷凝物的成分。烟灰和燃料物质在不凝性物中的后续燃烧导致一半的热量释放和污染物形成,并控制了煤粉火焰的稳定性。甚至挥发物的近似燃烧速率也是未知的,但是它们可以通过层流燃烧速度的测量来估计。在恒定体积的燃烧弹中测量层流燃烧速度,以测定来自6号病态烟煤和Dietz次烟煤的挥发物。挥发物是在辐射流反应器中产生的,该反应器先前已针对一次脱挥发分和二次热解进行了充分表征。对于来自6号州际煤炭的挥发物,当焦油的后半部分转化为烟灰时,燃烧速度增加了三倍,在空气中的当量比为0.7时达到150 cm / s。在增加的稀释水平下,二次热解的影响是相同的。对于Dietz煤中的挥发物,也观察到了二次热解的类似影响,但在相同条件下,其燃烧速度约为Ill.6的一半。通过以下相关性很好地描述了这些趋势:{美元} {美元} rm Ssb {lcub} u {rcub} sp2 = CXsb {lcub} O2 {rcub}(Xsb {lcub} H2 {rcub} + alpha Xsb {lcub} CH4 {rcub})exp({lcub}-{rcub} E / RTsb {lcub} f {rcub}){美元} {美元}其中燃料的变化以CH {美元} sb4的摩尔分数表示美元}和H {dollar} sb2 {dollar}。当量和稀释比确定{rm} Xsb {lcub} O2 {rcub} {美元}和火焰温度。该方程成功地将单一煤的所有数据在二次热解程度和当量比的较大范围内关联起来。但是,两种煤中挥发物的相关性需要不同的拟合参数。修改后的方程{dollar} {dollar} rm Ssb {lcub} u {rcub} sp2 = CXsb {lcub} O2 {rcub} Xsb {lcub} H2 {rcub} Xsb {lcub} CH4 {rcub} spalpha Xsb {lcub} CO {rcub} spbeta exp({lcub}-{rcub} E / RTsb {lcub} f {rcub}){dollar} {dollar}成功地使用一组拟合参数将两种煤的所有数据相关联。对于本研究的Ill。#6煤和Dietz煤,在430 K和1 atm的反应物温度和压力下,燃料当量比从0.4到1.1,烟灰比从0.5到1,以及(N {dollar} sb2 {美元} + CO {美元} sb2 {美元} + H {美元} sb2 {美元} O)/ O {美元} sb2 {美元}的比率从3.8到6.8,C = 2.7 {美元}乘以{美元} 10 {美元} sp4 {dollar} cm {dollar} sp2 {dollar} / s {dollar} sp2 {dollar},{dollar} alpha {dollar} = {dollar}-{dollar} 1.46,{dollar} beta {dollar} = {dollar }-{美元} 2.69,且E = 52.5大卡/摩尔。

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