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Counting Markov Equivalence Classes by Number of Immoralities

机译:计算Markov等当量课程的不道德

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Two directed acyclic graphs (DAGs) are called Markov equivalent if and only if they have the same underlying undirected graph (i.e. skeleton) and the same set of immoralities. When using observational data alone and typical identifiability assumptions, such as faithfulness, a DAG model can only be determined up to Markov equivalence. Therefore, it is desirable to understand the size and number of Markov equivalence classes (MECs) combinatorially. In this paper, we address this enumerative question using a pair of generating functions that encode the number and size of MECs on a skeleton G, and in doing so we connect this problem to classical problems in combinatorial optimization. The first generating function is a graph polynomial that counts the number of MECs on G by their number of immoralities. Using connections to the independent set problem, we show that computing a DAG on G with the maximum possible number of immoralities is NP-hard. The second generating function counts the MECs on G according to their size. Via computer enumeration, we show that this generating function is distinct for every connected graph on p nodes for all p ≤ 10.
机译:两个定向的非循环图(DAG)称为Markov当量如果且仅当它们具有相同的下面的无向图(即骨架)和相同的不道德集合。当使用单独观察数据和典型的可识别性假设(例如忠诚)时,只能确定DAG模型到马尔可夫等价。因此,希望了解组合的Markov等效类别(MEC)的大小和数量。在本文中,我们使用一对生成函数来解决这个枚举问题,该致函在骨架G上编码MEC的数量和大小,并在这样做时,我们将此问题连接到组合优化中的古典问题。第一生成功能是曲线图多项式,其通过它们的不道德的数量来计算G上的MEC。使用连接到独立的设置问题,我们表明,使用最大可能的不道德数量的G计算DAG是NP-HARD。第二生成函数根据其尺寸对G上的MEC进行计数。通过计算机枚举,我们表明,对于所有P≤10的P节点上的每个连接的图形都是不同的。

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