首页> 外文会议>Annual Waste Management Symposium >PRODUCTION AND REGENERATION OF SILVER(2) USED FOR DECONTAMINATION OF FACILITIES CONTAMINATED BY PUO2 AND DECOMPOSITION OF RADIOLOGICAL ORGANIC WASTE
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PRODUCTION AND REGENERATION OF SILVER(2) USED FOR DECONTAMINATION OF FACILITIES CONTAMINATED BY PUO2 AND DECOMPOSITION OF RADIOLOGICAL ORGANIC WASTE

机译:银(2)的生产和再生用于遗布污染PUO2污染的设施和放射性有机废弃物的分解

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A solution, which consists of Ag2+ ion and nitric acid is a very aggressive oxidant to PuO2 and organic compounds. Facilities contaminated by PuO2 can be decontaminated by this kind of solution when Pu4+ in PuO2 is oxidized by Ag2+ to Pu6+ and then PuO2 is dissolved into the solution. The radiological organic compounds can be decomposed by the solution of Ag2+ ion and nitric acid into CO2 and H2O, so the organic wastes are destroyed and the volume of organic wastes are reduced greatly. The method is very useful, but the key problem is the production and regeneration of Ag2+ ion, and it is difficult. In our experiments, a special electrochemical oxidization cell was designed and it is better than single compartment cell and membrane cell to produce and regenerate Ag2+ ion. The cell consists of two compartments as cathode compartment and anode compartment respectively. The two compartments are connected by a specially designed connector, so the solution can be interlinked. The solution in the anode compartment can be Ag+ and nitric acid, and nitric acid in cathode compartment. In the anode compartment, Ag+ is oxidized into Ag2+ and in cathode compartment, H+ is reduced into H2. During production of Ag2+, the reducing agent occurring in the cathode surface will be H2 mostly, and it will not consume the Ag2+. Consequently, Ag2+ is produced as desired. During regeneration of Ag2+, even other reducing agent occurred upon the surface of cathode because of introduced chemicals during the process of decontamination or decomposition, they will enter into anode compartment less and just consume a little of Ag2+. So the Ag2+ can be regenerated. In order to produce and regenerate Ag2+ in the anode compartment, several variables must be considered like structure of cell, length and diameter of the connector, solution composition in the cathode compartment, material of cathode and anode, current density, and the temperature of the solution. The optimum parameters are selected through our experiments to achieve high rate of production and regeneration of Ag2+ at low cost.
机译:由Ag2 +离子和硝酸组成的溶液是对PUO2和有机化合物的非常侵蚀的氧化剂。当Puo2的PU4 +通过Ag2 +至PU6 +氧化PU4 +氧化时,Puo2污染的设施可以通过这种解决方案进行净化,然后将Puo2溶解在溶液中。放射性有机化合物可以通过Ag2 +离子和硝酸的溶液分解成CO 2和H 2 O,因此有机废物被破坏,有机废物的体积大大减少。该方法非常有用,但关键问题是Ag2 +离子的生产和再生,很难。在我们的实验中,设计了一种特殊的电化学氧化细胞,并且优于单室细胞和膜细胞以产生和再生Ag2 +离子。该电池分别由两个隔室组成,分别为阴极舱和阳极隔室。这两个隔间通过专门设计的连接器连接,因此解决方案可以是互连的。阳极室中的溶液可以是Ag +和硝酸,阴极室中的硝酸。在阳极室中,Ag +被氧化成Ag2 +,在阴极室中,H +减少到H 2中。在Ag2 +的生产过程中,阴极表面发生的还原剂将主要是H2,并且不会消耗Ag2 +。因此,根据需要生产Ag2 +。在再生Ag2 +期间,由于在去污或分解过程中引入的化学物质,甚至在阴极表面时发生了其他还原剂,它们将进入阳极室的较少,并且仅消耗一定的ag2 +。所以AG2 +可以再生。为了在阳极隔室中生产和再生Ag2 +,必须考虑几个变量,如连接器的电池,长度和直径的结构,阴极室中的溶液组合物,阴极的材料和阳极,电流密度和温度解决方案。通过我们的实验选择最佳参数,以实现高成本的高生产率和ag2 +的高生产率和再生。

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