首页> 外文会议>Conference on Quanfum Optics, Optical Data Storage, and Advanced Microlithography >Probabilistic teleportation of two-unknown entangled atomic states without Bell-State measurement
【24h】

Probabilistic teleportation of two-unknown entangled atomic states without Bell-State measurement

机译:没有钟声测量的两个未知缠结原子状态的概率传送

获取原文

摘要

In this paper, we propose a protocol for teleportation of two unknown atomic states using non-maximally entangled states. We consider teleportation for atomic entangled states in cavity quantum electrodynamics ( QED ) . Through analysis, we conclude that it could be succeed without joint BSM (Bell-State measurement). One BSM can be exactly converted into two separate atomic measurements on the two relevant atoms only by one step using the interaction between the atoms and atoms in the cavity. The most remarkable advantage of our scheme is that the teleportation and distillation procedure can be carried out concurrently. Suppose that the cavity mode is prepared in vacuum state. We can utilize the Hamiltonian for the system, discussing how to make teleportation successful. And we discuss the probability of reconstructing the initial state. We consider two identical two-level atoms simultaneously interacting with a single-mode cavity field. There is no energy exchange between the atomic system and the cavity, so we use the detuned interaction between atoms and atoms in cavity in the scheme which is insensitive to both the cavity decay and the thermal field.
机译:在本文中,我们提出了一种使用非最大缠结状态对两个未知原子状态传送的协议。我们考虑传送腔量子电动力学(QED)中的原子缠结状态。通过分析,我们得出结论,没有联合BSM(钟声测量)可以成功。可以使用在腔中原子和原子之间的相互作用将一个BSM精确地转换成两个相关原子上的两个不同原子的原子测量。我们方案中最显着的优势在于传送和蒸馏程序可以同时进行。假设腔模式以真空状态制备。我们可以利用System的Hamiltonian,讨论如何使传送成功。我们讨论重建初始状态的概率。我们考虑两个相同的两级原子同时与单模腔场相互作用。原子系统和腔之间没有能量交换,因此我们在该方案中使用原子和原子之间的损伤相互作用,该方案中的腔体内的空腔与腔衰减和热场不敏感。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号