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State Complexity of GF(2)-inverse and GF(2)-star on Binary Languages

机译:GF(2)-Inverse和GF(2)-STAR的状态复杂性

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The GF(2)-inverse operation on formal languages is known to have state complexity 2~n + 1 for alphabets with at least three symbols, and 2~(n-1) + 1 for a one-symbol alphabet. In this paper, it is shown that, for a two-symbol alphabet, its state complexity is exactly 3/42~n + 3. For a more general operation of GF(2)-star, its state complexity for a binary alphabet remains 2~n + 1.
机译:已知对正式语言的GF(2) - vfse操作,用于具有至少三个符号的字母表的状态复杂性2〜n + 1,以及用于单符号字母的2〜(n-1)+ 1。在本文中,示出了对于两个符号字母,其状态复杂性正好是3/42〜n + 3.对于GF(2)-Star的更一般操作,其对二进制字母的状态复杂度仍然存在2〜n + 1。

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