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Parallel Repetition: Simplifications and the No-Signaling Case

机译:并行重复:简化和无信令盒

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Consider a game where a referee chooses (x, y) according to a publicly known distribution P{sub}(XY), sends x to Alice, and y to Bob. Without communicating with each other, Alice responds with a value a and Bob responds with a value b. Alice and Bob jointly win if a publicly known predicate Q(x, y, a, b) holds. Let such a game be given and assume that the maximum probability that Alice and Bob can win is v<1. Raz (SIAM J. Comput. 27, 1998) shows that if the game is repeated n times in parallel, then the probability that Alice and Bob win all games simultaneously is at most (v{top}-){sup}(n/log (s)), where s is the maximal number of possible responses from Alice and Bob in the initial game, and v{top}-<1 is a constant depending only on v. In this work, we simplify Raz's proof in various ways and thus shorten it significantly. Further we study the case where Alice and Bob are not restricted to local computations and can use any strategy which does not imply communication among them.
机译:考虑根据公知的分发P {sub}(xy)选择(x,y)的游戏,将x发送到Alice,y到Bob。在不互相通信的情况下,Alice以值A响应,并且Bob以值B响应。如果是公知的谓词Q(x,y,a,b),Alice和Bob共同赢得。让这样的游戏给出并假设Alice和Bob可以赢得的最大概率是V <1。 Raz(暹罗J. Comput。27,1998)表明,如果游戏并行重复n次,那么Alice和Bob同时赢得所有游戏的概率最多(v {top} - ){sup}(n /日志),其中S是初始游戏中的Alice和Bob可能响应的最大数量,而V {TOP} - <1是常量,其仅取决于v。在这项工作中,我们简化了raz的各种证明方式,从而显着缩短。此外,我们研究了Alice和Bob不限于本地计算的情况,并且可以使用不暗示其中沟通的任何策略。

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