首页> 外文会议>International Symposium on Combustion >MECHANISMS AND RATES OF THE REACTIONS C{sub}2H{sub}5+O AND 1-C{sub3H{sub}7+ O
【24h】

MECHANISMS AND RATES OF THE REACTIONS C{sub}2H{sub}5+O AND 1-C{sub3H{sub}7+ O

机译:反应的机制和速率c {sub} 2h {sub} 5 + o和1-c {sub 3h {sub} 7+ o

获取原文

摘要

The mechanisms and rates of the reactions of the primary alkyl radicals ethyl and l-propyl with oxygen atoms at room temperature and low pressure (around 5 mbar) have been studied using two independent experimental arrangements. The reactants were generated by UV-laser flash photolysis with different precursors (C{sub}2H{sub}5COC{sub}2H{sub}5, C{sub}2H{sub}6+CFCl{sub}3, C{sub}2H{sub}5I, C{sub}3H{sub}7COC{sub}3H{sub}7, SO{sub}2). Stable species concentrations were measured quantitatively by Fourier transform IR and OH radical concentrations of the ground (v = 0) and first vibrational (v = 1) state by time-resolved laser-induced fluorescence. For both reaction 1 and reaction 2, the mechanism is explained in terms of the formation and subsequent decomposition of a chemically activated alkoxy radical and a competing abstraction channel leading directly to OH and the alkene: C{sub}2H{sub}5+O→C{sub}2H{sub}5O* (reaction 1a)/C{sub}2H{sub}5O*→HCHO+CH{sub}3 (reaction la{sub}1)/ CH{sub}3CHO+H (reaction la{sub}2)//C{sub}2H{sub}5+O→C{sub}2H{sub}4 +OH (reaction 1b). The absolute branching ratio was determined preferentially using diethyl ketone as the C{sub}2H{sub}5 radical source leading to (1a{sub}1)/(1a{sub}2)/(1b), 32/44/24. Relative branching ratios for the C{sub}2H{sub}5 radical sources C{sub}2H{sub}6+Cl and C{sub}2H{sub}5I were derived as (1a{sub}1)/(1a{sub}2)=1/1.5 and 1/1.55, respectively. The overall rate coefficient of the reaction C{sub}2H{sub}5+ O was measured as k{sub}1=(1.04±0.1)×10{sup}14 cm{sup}3 mol{sup}-1 s{sup}-1 and in addition k(C{sub}2H{sub}5+OH)=(7.0±1)×10{sup}13 cm{sup}3 mol{sup}-1 s{sup}-1. The mechanism and the rate of reaction 2 were found as 1-C{sub}3H{sub}7 +O→1-C{sub}3H{sub}7O* (reaction 2a)/ 1-C{sub}3H{sub}7O*→ HCHO+C{sub}2H{sub}5 (reaction 2a{sub}1)/C{sub}2H{sub}5CHO+H (reaction 2a{sub}2)//1-C{sub}3H{sub}7+O→C{sub}3H{sub}6+OH (reaction 2b) (branching ratio (2a{sub}1)/(2a{sub}2)/(2b), 44/ 32/ 24) and k{sub}2= (8.2±1)×10{sup}13 cm{sup}3 mol{sup}-1 s{sup}-1. The results are discussed in terms of statistical rate theory.
机译:机制和伯烷基自由基的反应速率乙基和在室温下和低压(约5毫巴)使用两个独立的实验安排已经研究了1-丙基氧原子。通过UV-激光闪光光解与不同的前体(C {子} 2H {子} 5COC {子} 2H {子} 5,C {子} 2H {子} 6 + CFCL {子} 3,C {生成的反应物子} 2H {子} 5I,C {}子3H {子} 7COC {子} 3H {子} 7,SO {子} 2)。稳定物质浓度定量测定由傅立叶通过时间分辨激光诱导荧光变换IR和接地(V = 0)和第一振动(V = 1)的状态的OH基浓度。 13 C {子} 2H {子} 5 + O:对于这两个反应1和反应2,该机构在形成和化学激活烷氧基的后续分解和竞争抽象通道直接通向OH和烯烃方面解释→C {子} 2H {子} 50 *(反应1a)中/ C {子} 2H {子} 50 *→HCHO + CH {子} 3(反应LA {子} 1)/ CH {子} 3CHO + H (反应LA {子} 2)// C {子} 2H {子} 5 + O→C {子} 2H {子} 4 + OH(反应1B)。绝对分支比被确定优先使用二乙基酮的C {子} 2H {子} 5原子团源,导致(1A {子} 1)/(1A {子} 2)/(1b)中,32/44/24 。相对分支比为C {子} 2H {子} 5个自由基源13 C {子} 2H {子} 6 + Cl和13 C {子} 2H {子} 5I分别导出(1A {子} 1)/(1A {子} 2)=分别为1 / 1.5和1 / 1.55。反应13 C {子} 2H {子}的总速率系数5+ O的测定为k {子} 1 =(1.04±0.1)×10 {SUP}14厘米{SUP} 3摩尔{SUP} -1 S {SUP} -1-并且除了K(13 C {子} 2H {子} 5 + OH)=(7.0±1)×10 {SUP}13厘米{SUP} 3摩尔{SUP} -1 S {SUP} - 1。机理和反应2的速率被发现为1-C {子} 3H {子} 7 + O→1-C {子} 3H {子} 70 *(反应2A)/ 1-C {子} 3H {子} 70 *→HCHO + C {子} 2H {子} 5(反应图2a {子} 1)/ C {子} 2H {子} 5CHO + H(反应图2a {子} 2)// 1-C {子} 3H {子} 7 + O→C {子} 3H {子} 6 + OH(反应图2b)(分支比(2A {子} 1)/(2A {子} 2)/(2b)中,44 / 24分之32)和k {子} 2 =(8.2±1)×10 {SUP}13厘米{SUP} 3摩尔{SUP} -1 S {SUP} -1。结果在统计速率理论的角度来讨论。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号