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Binary Codes for Collusion-Secure Fingerprinting

机译:用于串集的串可规的二进制代码

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We examine the problem of Collusion-Secure Fingerprinting in the case when marks are binary and coalitions are of size 2. We are motivated by two considerations, the pirates' probablity of success (which must be non-zero, as was shown by Boneh and Shaw) on one hand, and decoding complexity on the other. We show how to minimize the pirates' probability of success: but the associated decoding complexity is O(M~2), where M is the number of users. Next we analyze the Boneh and Shaw replication strategy which features a higher probability of success for the pirates but a lower decoding complexity. There are two variations. In the case when the fingerprinting code is linear we show that the best codes are linear intersecting codes and that the decoding complexity drops to O(log~2 M). In the case when the fingerprinting code is allowed to be nonlinear, finding the best code amounts to finding the largest B_2-sequence of binary vectors, an old code amounts to finding the largest B_2-sequence of binary vectors, and old combinatorial problem. In that case decoding complexity is intermediate, namely O(M).
机译:在标记为二进制和联盟的情况下,我们检查勾结安全指纹识别的问题。我们的激励是两次考虑因素,海盗的成功概率(这必须是非零的,如Boneh所示肖一方面)一方面,并​​在另一方面解码复杂性。我们展示了如何最大限度地减少海盗成功概率:但相关的解码复杂性是O(m〜2),其中M是用户的数量。接下来,我们分析BOILH和SHAW复制策略,该策略具有更高的海盗成功概率,而是较低的解码复杂性。有两个变化。在指纹识别代码是线性的情况下,我们显示最佳代码是线性交叉代码,并且解码复杂度下降到O(log〜2 m)。在允许指纹码的情况下是非线性的,找到最佳代码,以查找二进制向量的最大B_2序列,旧的代码是找到最大的B_2 - 二进制矢量序列和旧的组合问题。在这种情况下,解码复杂性是中间的,即O(m)。

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