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Two-Party Private Vector Dominance: The All-Or-Nothing Deal

机译:两方私人媒介主导地位:全有或全无

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Alice holds a secret integer a while Bob holds a secret integer b, they want to decide on the predicate a > b with no information revealed other than the result. This is the well known Yao’s millionaires’ problem. In some ecommerce applications, Alice holds an n-dimension secret vector a = (a1, ..., an) while Bob holds an n-dimension secret vector ß = (b1, ..., bn). Alice and Bob want to decide on one of the three possible domination results, a succ ß, ß succ a, or no domination exists, with no information revealed other than the result. I.e., in case there is a domination, no information is revealed about any dimension, whereas, in case no domination exists, no information is revealed about the predicate ai > bi for any i = 1, ..., n. In the honest-but-curious scenario and without the help of a third party, in this paper we propose an efficient solution to this problem. We give a complete security proof. Up to our knowledge, no practical solution to this problem — that does not incorporate a third party — has been proposed.
机译:爱丽丝(Alice)拥有一个秘密整数a,而鲍勃(Bob)拥有一个秘密整数b,他们想确定谓词a> b,除了结果外没有其他信息。这是众所周知的姚明的百万富翁问题。在某些电子商务应用程序中,爱丽丝持有n维秘密向量a =(a1,...,an),而鲍勃持有n维秘密向量ß=(b1,...,bn)。爱丽丝(Alice)和鲍勃(Bob)想要确定三种可能的控制结果之一:成功,成功或不存在,除了结果外没有其他信息。即,在存在支配性的情况下,不会透露任何维数的信息,而在不存在支配性的情况下,对于任何i = 1,...,n的谓词ai> bi都不会显示任何信息。在诚实但又好奇的情况下,在没有第三方帮助的情况下,本文提出了一种有效的解决方案。我们提供完整的安全证明。据我们所知,尚未提出解决该问题的切实可行的解决方案-该方案不包含第三方。

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