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Tight Approximation Bounds for Maximum Multi-coverage

机译:紧密的近似界以实现最大的多重覆盖

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In the classic maximum coverage problem, we are given subsets T_1,..., T_m of a universe [n] along with an integer k and the objective is to find a subset S (∈ )[m] of size k that maximizes C(S):= | ∪_i∈S T_i|. It is well-known that the greedy algorithm for this problem achieves an approximation ratio of (1 - e~(-1)) and there is a matching inapproximabil-ity result. We note that in the maximum coverage problem if an element e ∈ [n] is covered by several sets, it is still counted only once. By contrast, if we change the problem and count each element e as many times as it is covered, then we obtain a linear objective function, C~((∞))(S) = Σ_(i∈S ) |T_i|, which can be easily maximized under a cardinality constraint. We study the maximum ℓ-multi-coverage problem which naturally interpolates between these two extremes. In this problem, an element can be counted up to £ times but no more; hence, we consider maximizing the function C~((ℓ))(S) = Σ_(e∈[n]) min{ℓ |{i∈S : e ∈ T_i}|}, subject to the constraint |S| ≤ k. Note that the case of ℓ = 1 corresponds to the standard maximum coverage setting and ℓ = ∞ gives us a linear objective. We develop an efficient approximation algorithm that achieves an approximation ratio of 1 -ℓ~ℓ_e-ℓ/ℓ! for the ℓ-multi-coverage problem. In particular, when ℓ = 2, this factor is 1 - 2e~(-2) ≈ 0.73 and as ℓ grows the approximation ratio behaves as 1 - 1/2πℓ~(1/2). We also prove that this approximation ratio is tight, i.e., establish a matching hardness-of-approximation result, under the Unique Games Conjecture. This problem is motivated by the question of finding a code that optimizes the list-decoding success probability for a given noisy channel. We show how the multi-coverage problem can be relevant in other contexts, such as combinatorial auctions.
机译:在经典的最大覆盖率问题中,我们获得了宇宙[n]的子集T_1,...,T_m以及整数k,目的是找到大小为k的子集S(∈)[m],该子集最大化C (S):= | ∪_i∈ST_i |。众所周知,针对此问题的贪婪算法实现了(1- e〜(-1))的近似比率,并且具有匹配的近似度结果。我们注意到,在最大覆盖率问题中,如果元素e∈[n]被多个集合覆盖,则它仍仅被计数一次。相反,如果我们改变问题并计算每个元素e的覆盖次数,则可以获得线性目标函数C〜((∞))(S)=Σ_(i∈S)| T_i |,在基数约束下可以很容易地将其最大化。我们研究了在这两个极端之间自然插值的最大multi-多重覆盖问题。在这个问题中,一个元素最多可以计数£次,但不能再多。因此,我们考虑将函数C〜((ℓ))(S)=Σ_(e∈[n])min {ℓ| {i∈S:e∈T_i} |}最大化。 ≤k。请注意,the = 1的情况对应于标准最大覆盖范围设置,ℓ=∞给出的是线性目标。我们开发了一种有效的近似算法,可以实现1-ℓ〜ℓ_e-ℓ/ℓ的逼近率! ℓ-多重覆盖问题。特别地,当ℓ= 2时,该因子为1-2e〜(-2)≈0.73,随着ℓ的增大,近似比表现为1-1 /2πℓ〜(1/2)。我们还证明了这种近似比率是紧密的,即在唯一游戏猜想下建立了匹配的近似硬度结果。这个问题是由找到一个代码的问题引起的,该代码可以优化给定噪声信道的列表解码成功率。我们展示了在其他情况下(例如组合拍卖)多覆盖问题是如何相关的。

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