The cyclability of a graph is the maximum integer k for which every k vertices lie on a cycle. The algorithmic version of the problem, given a graph G and a non-negative integer k, decide whether the cyclability of G is at least k, is NP-hard. We prove that this problem, parameterized by k, is co-W[1]-hard. We give an FPT algorithm for planar graphs that runs in time 2~(2~(O(k~2 log k))) • n~2. Our algorithm is based on a series of graph theoretical results on cyclic linkages in planar graphs.
展开▼
