首页> 外文会议>IEA 2011;International conference on information engineering and applications >On Diophantine Equation X(X+1)(X+2)(X+3) = 15Y(Y+1)(Y+2)(Y+3)s
【24h】

On Diophantine Equation X(X+1)(X+2)(X+3) = 15Y(Y+1)(Y+2)(Y+3)s

机译:关于丢番图方程X(X + 1)(X + 2)(X + 3)= 15Y(Y + 1)(Y + 2)(Y + 3)s

获取原文

摘要

Several scholars [1, 2, 3, 4, 5, 6, 7] have studied the Diophantine equation X(X+1)(X+2)(X+3)=DY(Y+1)(Y+2)(Y+3)(1) Where D is a positive integer solutions of Eq.(l) have been obtained by Cohn[l], Ponnudu-ral [2], Xuan [3], Luo[ 4, 5], and Duan [6, 7]. However, for the case D=15, Eq.(1) still remains open.
机译:几位学者[1,2,3,4,5,6,7]研究了Diophantine方程X(X + 1)(X + 2)(X + 3)= DY(Y + 1)(Y + 2) (Y + 3)(1)其中D是等式(l)的正整数解,已通过Cohn [l],Ponnudural [2],Xuan [3],Luo [4、5]和段[6,7]。但是,对于D = 15的情况,方程(1)仍然保持打开状态。

著录项

相似文献

  • 外文文献
  • 中文文献
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号