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Computing the Top-k Maximal Answers in a Join of Ranked Lists

机译:计算排名列表联接中的前k个最大答案

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Complex search tasks that utilize information from several data sources, are answered by integrating the results of distinct basic search queries. In such integration, each basic query returns a ranked list of items, and the main task is to compute the join of these lists, returning the top-k combinations. Computing the top-k join of ranked lists has been studied extensively for the case where the answer comprises merely complete combinations. However, a join is a lossy operation, and over heterogeneous data sources some highly-ranked items, from the results of the basic queries, may not appear in any combination. Yet, such items and the partial combinations in which they appear may still be relevant answers and should not be discarded categorically. In this paper we consider a join where combinations are padded by nulls for missing items. A combination is maximal if it cannot be extended by replacing a null by an item. We present algorithms for computing the top-k maximal combinations and provide an experimental evaluation.
机译:利用来自多个数据源的信息的复杂搜索任务,可以通过整合不同的基本搜索查询的结果来回答。在这种集成中,每个基本查询都返回一个已排序的项目列表,主要任务是计算这些列表的联接,并返回前k个组合。对于答案仅包含完整组合的情况,已经广泛研究了计算排名列表的前k个连接。但是,联接是一种有损操作,并且在异构数据源上,一些基本查询结果中排名较高的项可能不会以任何组合出现。但是,此类项目及其出现的部分组合可能仍然是相关的答案,不应分类丢弃。在本文中,我们考虑一个联接,其中缺失项的组合用空值填充。如果不能通过用项目替换null来扩展组合,则该组合是最大的。我们提出了用于计算前k个最大组合的算法,并提供了实验评估。

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