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On an equation involving the Smarandache reciprocal function and its positive integer solutions

机译:关于包含Smarandache倒数函数的方程及其正整数解

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For any positive integer n, the Smarandache reciprocal function Sc(n) is defined as Sc(n) = max{m : y|n! for all 1≤y≤m, and m+1+n!}. That is, Sc(n) is the largest positive integer m such that y|n! for all integers 1≤y≤m. The main purpose of this paper is using the elementary method and the Vinogradov's important work to prove the following conclusion: For any positive integer k≥3, there exist infinite group positive integers (m1, m2,…, mk) such that the equation Sc(m1+m2+…+mk)=Sc(m1+Sc(m2)+…+Sc(mk).This solved a problem posed by Zhang Wenpeng during the Fourth International Conference on Number Theory and the Smarandache Problems.
机译:对于任何正整数n,Smarandache倒数函数Sc(n)定义为Sc(n)= max {m:y | n!对于所有1≤y≤m,以及m + 1 + n!}。即,Sc(n)是最大正整数m,使得y | n!对于所有1≤y≤m的整数。本文的主要目的是使用基本方法和维诺格拉多夫的重要工作来证明以下结论:对于任何k≥3的正整数,存在无限组正整数(m1,m2,…,mk),使得方程式Sc (m1 + m2 +…+ mk)= Sc(m1 + Sc(m2)+ ... + Sc(mk)。这解决了张文鹏在第四届国际数论会议上提出的问题和Smarandache问题。

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