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Quenched steels with optimum hardenability - obtd. by using specific amts. of boron, nitrogen, aluminium, and titanium and/or zirconium
Quenched steels with optimum hardenability - obtd. by using specific amts. of boron, nitrogen, aluminium, and titanium and/or zirconium
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机译：具有最佳淬透性的淬火钢-obtd。通过使用特定的弹药。硼，氮，铝和钛和/或锆
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Borom steels in the quenched or case-hardened and quenched condition, with improved hardness and strength due to the optimum amts. of soluble boron (Bs) and insol B(B1). The total B(Bt) and effective N2(Ne) in ppm. comply with the formula:- 10Ne-18Bt - SO= -300+200; where Bt=20-60 ppm; Ne=N-Ti/5-Zr/10, all being in ppm. and N=total N2= 40-190; Ti + Zr/2 = 100-300 ppm. and the Ti or the Zr may be zero; Ne is min. 20ppm. So is the Al equiv. and =Al + V/1.9 + Nb/3.4 + Ta/6.7 and So=100-400ppm., esp. 200-400 ppm. when Bt is 30-60 ppm. The above addns. are prepd. made after careful deoxidn. of the steel. The above ratios of B, N2, Al, plus Ti and/or Zr provide optimum hardenability.
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机译：处于淬火或表面淬火和淬火状态的Borom钢，由于具有最佳的抗磨性而具有更高的硬度和强度。可溶性硼（Bs）和溶胶B（B1）。总B（Bt）和有效N2（Ne），以ppm为单位。符合公式：-10Ne-18Bt-SO = -300 + 200;其中Bt ＝ 20-60ppm; Ne ＝ N-Ti / 5-Zr / 10，均为ppm。 N ＝总N 2 ＝ 40-190; Ti + Zr / 2 = 100-300 ppm。 Ti或Zr可以为零; Ne是最小的。 20ppm。铝当量也是如此。并且＝ Al + V / 1.9 + Nb / 3.4 + Ta / 6.7，且So ＝ 100-400ppm。 200-400 ppm。当Bt为30-60 ppm时。上面的addns。准备好了。仔细脱氧后制成。钢。 B，N 2，Al以及Ti和/或Zr的上述比率提供了最佳的淬透性。
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